--%>

Problem on mol fraction of naphthalene

At 20°C the solubility of solid naphthalene in hexane is 0.09 mol/mol of solution. Use this information and the data below to estimate the following for this system:

a) The mol fraction of naphthalene in the vapour phase in equilibrium with a saturated solution of naphthalene at 20oC.

b) The mol fraction of naphthalene in the vapor phase in equilibrium with a liquid containing 5.0 mol% naphthalene and 95 mol% hexane at 20°C.

c) The solubility of naphthalene in hexane at 40oc

Data:

Heat of melting of naphthalene: 4610 cal/mol
Heat of melting of hexane: 3119 cal/mol
Melting point of naphthalene: 80.2oC
Melting point of hexane: -95oC

Vapor pressure at 20°C:
solid naphthalene: 0.054 mmHg
liquid hexane: 122.5 mmHg

The activity coefficients of naphthalene and hexane in the liquid solution can be represented by the Regular Solution model

RT ln γA = αXB2

RT ln γB = αXA2

where α is a constant independent of temperature and composition.

   Related Questions in Chemistry

  • Q : Molecular Diameters The excluded volume

    The excluded volume b, introduced by vander Wall's as an empirical correction term, can be related to the size gas molecules. To do so, we assume the excluded volume is the result of the pairwise coming together of molecules. This assumption is justified when b values

  • Q : Problem on Redlich-Kwong equation i)

    i) Welcome to Beaver Gas Co.! Your first task is to calculate the annual gross sales of our superpure-grade nitrogen and oxygen gases. a) The total gross sales of N2 is 30,000 units. Take the volume of the cylinder to be

  • Q : HCl polarity Illustrate HCl is polar or

    Illustrate HCl is polar or non-polar?

  • Q : Illustrations of the reversible reaction

    What are the various illustrations of the reversible reaction? Explain briefly?

  • Q : Problem on molality Select the right

    Select the right answer of the question. Calculate the molality of 1 litre solution of 93% H2SO4 (weight/volume). The density of the solution is 1.84 g /ml : (a) 10.43 (b) 20.36 (c) 12.05 (d) 14.05

  • Q : P- block why pentahalids are more

    why pentahalids are more covalent than tetrahalids

  • Q : Problem based on molarity Select the

    Select the right answer of the question. If 18 gm of glucose (C6H12O6) is present in 1000 gm of an aqueous solution of glucose, it is said to be: (a)1 molal (b)1.1 molal (c)0.5 molal (d)0.1 molal

  • Q : Liquid Vapour Free Energies The free

    The free energy of a component of a liquid solution is equal to its free energy in the equilibrium vapour.Partial molal free energies let us deal with the free energy of the components of a solution. We use these free energies, or simpler concentration ter

  • Q : Mole fraction of benzene Choose the

    Choose the right answer from following. In a solution of 8.7g benzene C6H6 and 46.0 gm toluene ,(C6, H5, CH3) the mole fraction of benzene in this solution is: (a)1/6 (b)1/5 (c)1/2 (d)1/3

  • Q : Law of multiple proportions and Law of

    Describe the difference between law of multiple proportions and law of definite proportions?