HCl polarity
Illustrate HCl is polar or non-polar?
Expert
Yes, HCl is the polar compound because chlorine is more electronegative than the H It attract a bond pair towards itself. Therefore, compound is a polar.
A 500 gm tooth paste sample has 0.2g fluoride concentration. Determine the concentration of F in terms of ppm level: (a) 250 (b) 200 (c) 400 (d) 1000Answer: (c) F-ions in ppm = (0.2/500) x 106 = 400
Colligative properties of a solution depends upon: (a) Nature of both solvent and solute (b) The relative number of solute and solvent particles (c) Nature of solute only (d) Nature of solvent only
list and identify differences between the major classes of hydrocarbons
The boiling point of a solution of 0.11 gm of a substance in 15 gm of ether was found to be 0.1oC higher than that of the pure ether. The molecular weight of the substance will be (Kb = 2.16) (a) 148 &nbs
The freezing point of a solution having 4.8 g of a compound in 60 g of benzene is 4.48. Determine the molar mass of the compound (Kf = 5.1 Km-1) , (freezing point of benzene = 5.5oC) &n
The following mixture of hydrocarbons is obtained as one stream in a petroleum refinery. Q : Particles of quartz Particles of quartz Particles of quartz are packed by:(i) Electrical attraction forces (ii) Vander Waal's forces (iii) Covalent bond forces (iv) Strong electrostatic force of attraction Answer: (iii)
Particles of quartz are packed by:(i) Electrical attraction forces (ii) Vander Waal's forces (iii) Covalent bond forces (iv) Strong electrostatic force of attraction Answer: (iii)
Give me answer of this question. If 20ml of 0.4N, NaoH solution completely neutralises 40ml of a dibasic acid. The molarity of the acid solution is:(a) 0.1M (b) 0.2M (c)0.3M (d)0.4M
Select the right answer of the question .The molarity of a 0.2 N N2Co3 solution will be: (a) 0.05 M (b) 0.2 M (c) 0.1 M (d)0.4 M
What is the utilization of glacial acetic acid? Briefly describe the uses.
18,76,764
1934199 Asked
3,689
Active Tutors
1453522
Questions Answered
Start Excelling in your courses, Ask an Expert and get answers for your homework and assignments!!