Law of multiple proportions and Law of definite proportions
Describe the difference between law of multiple proportions and law of definite proportions?
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Both laws have to do with linking to Dalton's Atomic Theory. The difference is only that Law of Definite Proportions deals with the elements joining to form ONE compound in a simple whole number ratio. Law of Multiple Proportions is comparing the same two elements which make up two different compounds a division of these 2 ratios should equal a simple whole number ratio. As, Carbon and oxygen can add to form carbon monoxide and carbon dioxide. If you calculated every compounds ration of oxygen to carbon, we could get following ratios: compound A would equal a combining the ratio of 1.34:1 (O:C). Compound B would equal to combining ratio of 2.67:1 (O: C). If we divided bigger ratio by smaller ratio we should have that oxygen combines with a ratio of 2.67/1.34 that would be equal 1.99:1, which is close to 2:1.
Liquefied natural gas (LNG) is produced using a Linde liquefaction process from pure methane gas at 3 bar and 280 K (conditions at point 1 in figure below). A three-stage compressor with interceding is used to compress the methane to 100 bar (point 2). The first stage
Can someone please help me in getting through this problem. Which of the given concentration factor is affected by the change in temperature: (1) Molarity (2) Molality (3) Mole fraction (4) Weight fraction
Alkyl halides can be prepared from alkanes through substitution and from alkenes through addition of halogen acids or through allylic substitution. From alkanesWhen alkanes are treated with halogens, chlo
Select the right answer of the question.10ml of conc.H2SO4 (18 molar) is diluted to 1 litre. The approximate strength of dilute acid could be: (a)0.18 N (b)0.09 N (c) 0.36 N (d)1800 N
Choose the right answer from following. The amount of NaOH in gms in 250cm3 of a0.100M NaOH solution would be : (a) 4 gm (b) 2 gm (c) 1 gm (d) 2.5 gm
The freezing point of a solution having 4.8 g of a compound in 60 g of benzene is 4.48. Determine the molar mass of the compound (Kf = 5.1 Km-1) , (freezing point of benzene = 5.5oC) &n
These are polymers that can be broken into small segments by enzyme-catalysed reactions. The required enzymes are produced by microorganism. It is a known fact that the carbon-carbon bonds of chain growth polymers are inert to enzyme-catalysed reactions, and hence they are non biod
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how 0.5N HCL is prepared for 10 littre solution
Give me answer of this question. In a mixture of 1 gm H2 and 8 gm O2 , the mole fraction of hydrogen is: (a) 0.667 (b) 0.5 (c) 0.33 (d) None of these
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