Law of multiple proportions and Law of definite proportions
Describe the difference between law of multiple proportions and law of definite proportions?
Expert
Both laws have to do with linking to Dalton's Atomic Theory. The difference is only that Law of Definite Proportions deals with the elements joining to form ONE compound in a simple whole number ratio. Law of Multiple Proportions is comparing the same two elements which make up two different compounds a division of these 2 ratios should equal a simple whole number ratio. As, Carbon and oxygen can add to form carbon monoxide and carbon dioxide. If you calculated every compounds ration of oxygen to carbon, we could get following ratios: compound A would equal a combining the ratio of 1.34:1 (O:C). Compound B would equal to combining ratio of 2.67:1 (O: C). If we divided bigger ratio by smaller ratio we should have that oxygen combines with a ratio of 2.67/1.34 that would be equal 1.99:1, which is close to 2:1.
What type of bond does HCl encompass? Describe briefly?
order of decreasing basicity of urea and its substituents
what is the equation for calculating molar mass of non volatile solute
When a catalyst mixes homogeneously with the reactants and forms a single phase, the catalyst is said to be homogeneous and this type of catalysis is called homogeneous catalysis. Some more examples of homogeneous catalysis are: SO2
This is the common method for preparing haloalkanes in laboratory. Alcohols can be converted to haloalkanes by substitution of - OH group with a halogen atom. Different reagents can be used to get haloa
The Schrodinger wave equation generalizes the fitting-in-of-waves procedure.The waves that "fit" into the region to which the particle is contained can be recognized "by inspection" only for a few simple systems. For other problem a mathematical procedure
Choose the right answer from following. The molality of 90% H2SO4 solution is: [density=1.8 gm/ml] (a)1.8 (b) 48.4 (c) 9.18 (d) 94.6
Give me answer of this question. When a non-volatile solute is dissolved in a solvent, the relative lowering of vapour pressure is equal to: (a) Mole fraction of solute (b) Mole fraction of solvent (c) Concentration of the solute in grams per litre
Superphosphate has the formula CaH4(PO4)2 H2O, what is the calculation to get the percentage of Phosphorus, I need to show the calculation. I know it is 30.9737622 u in weight and 2 atoms of the formula, but not sure how to work the calculation backwards.
Choose the right answer from following. If P and P are the vapour pressure of a solvent and its solution respectively N1 and N2 and are the mole fractions of the solvent and solute respectively, then correct relation is: (a) P= PoN1 (b) P= Po N2 (c)P0= N2 (d)
18,76,764
1932899 Asked
3,689
Active Tutors
1422693
Questions Answered
Start Excelling in your courses, Ask an Expert and get answers for your homework and assignments!!