Procedure for separating the components of the gun-powder
Briefly describe the procedure for separating the components of the gun-powder?
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At first introduce water and then filter the particulates out. The liquid would be mainly potassium nitrate as there will be a finite quantity of solubility of the other two compounds. Next introduce the carbon disulfide and filter the carbon away from the soluble sulphur. They would be cleaned up adequately enough.
20mol of hcl solution requires 19.85ml of 0.01 M NAOH solution for complete neutralisation. the molarity of hcl solution
The free energy of a component of a liquid solution is equal to its free energy in the equilibrium vapour.Partial molal free energies let us deal with the free energy of the components of a solution. We use these free energies, or simpler concentration ter
order of decreasing basicity of urea and its substituents
When 5.85 g of NaCl (having molecular weight 58.5) is dissolved in water and the solution is prepared to 0.5 litres, the molarity of the solution is: (i) 0.2 (ii) 0.4 (iii) 1.0 (iv) 0.1
Describe all the kinds of insulators which are present?
The accuracy of your written English will be taken into account in marking. 1. (a) Identify the spectator ions in the following equation &nb
Among the below shown which crystal will be soft and have low melting point: (a) Covalent (b) Ionic (c) Metallic (d) MolecularAnswer: (d) Molecular crystals are soft and have low melting point.
Help me to go through this problem. Molecular weight of glucose is 180. A solution of glucose which contains 18 gms per litre is : (a) 2 molal (b) 1 molal (c) 0.1 molal (d)18 molal
To meet human needs, scientists have started preparing synthetic rubbers. Besides having similar properties as natural rubbers they are tougher, more flexible and more durable than natural rubber. They are capable of getting stretched to twice its length. Though, it reverts to its original shape
Can someone please help me in getting through this problem. 1.0 gm of pure calcium carbonate was found to require 50 ml of dilute HCL for complete reaction. The strength of the HCL solution is given by: (a) 4 N (b) 2 N (c) 0.4 N (d) 0.2 N
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