Procedure for separating the components of the gun-powder
Briefly describe the procedure for separating the components of the gun-powder?
Expert
At first introduce water and then filter the particulates out. The liquid would be mainly potassium nitrate as there will be a finite quantity of solubility of the other two compounds. Next introduce the carbon disulfide and filter the carbon away from the soluble sulphur. They would be cleaned up adequately enough.
Explain how dissolving the Group IV carbonate precipitate with 6M CH3COOH, followed by the addition of extra acetic acid.
Help me to go through this problem. 6.02x 1020 molecules of urea are present in 100 ml of its solution. The concentration of urea solution is: (a) 0.02 M (b) 0.01 M (c) 0.001 M (d) 0.1 M (Avogadro constant, N4= 6.02x 1023mol -1)<
The number of moles of a solute in its solution is 20 and total no. of moles are 80. The mole fraction of solute wil be: (a) 2.5 (b) 0.25 (c) 1 (d) 0.75
What will be the molality of a solution containing 18g of glucose (having mol. wt. = 180) dissolved in 500g of water: (i) 1m (ii) 0.5m (iii) 0.2m (iv) 2m
Help me to go through this problem. Molarity of a solution containing 1g NaOH in 250ml of solution: (a) 0.1M (b) 1M (c) 0.01M (d) 0.001M
Choose the right answer from following. For a solution of volatile liquids the partial vapour pressure of each component in solution is directly proportional to: (a) Molarity (b) Mole fraction (c) Molality (d) Normality
Alkyl halides or haloalkanes are the compounds in which a halogen is bonded to an alkyl group. They have the general formula RX (where R is alkyl grou
The accuracy of your written English will be taken into account in marking. 1. (a) Identify the spectator ions in the following equation &nb
Provide solution of this question. In an experiment, 1 g of a non-volatile solute was dissolved in 100 g of acetone (mol. mass = 58) at 298K. The vapour pressure of the solution was found to be 192.5 mm Hg. The molecular weight of the solute is (vapour pressure of ace
Can someone please help me in getting through this problem. The solution ofAl2(SO4)3 d = 1.253gm/m comprise 22% salt by weight. The molarity, normality and molality of the solution is: (1) 0.805 M, 4.83 N, 0.825 M (2)
18,76,764
1922836 Asked
3,689
Active Tutors
1450460
Questions Answered
Start Excelling in your courses, Ask an Expert and get answers for your homework and assignments!!