Procedure for separating the components of the gun-powder
Briefly describe the procedure for separating the components of the gun-powder?
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At first introduce water and then filter the particulates out. The liquid would be mainly potassium nitrate as there will be a finite quantity of solubility of the other two compounds. Next introduce the carbon disulfide and filter the carbon away from the soluble sulphur. They would be cleaned up adequately enough.
Select right answer of the question. A dry air is passed through the solution, containing the 10 gm of solute and 90 gm of water and then it pass through pure water. There is the depression in weight of solution wt by 2.5 gm and in weight of pure solvent by 0.05 gm. C
Briefly state the wavelengths which the human eye can see?
Benzene and toluene form nearly ideal solutions. At 20°C, the vapour pressure of benzene is 75 torr and that of toluene is 22 torr. The parial vapour pressure of benzene at 20°C for a solution containing 78g of benzene and 46g of toluene in torr is: (a) 50 (b)
Describe the dipole moment of chloro-octane in brief?
Briefly describe the difference in the Mendeleev’s table and modern periodic table?
Help me to go through this problem. 1000 gms aqueous solution of CaCO3 contains 10 gms of carbonate. Concentration of the solution is : (a)10 ppm (b)100 ppm (c)1000 ppm (d)10000 ppm
Superphosphate has the formulae: CaH4 (PO4)2H2). Calculate the percentage of phosphorus in this chemical. Show your calculations (around ten lines); also Work out how to make up a nutrient mixtur
Give me answer of this question. In a mixture of 1 gm H2 and 8 gm O2 , the mole fraction of hydrogen is: (a) 0.667 (b) 0.5 (c) 0.33 (d) None of these
The equilibrium constant can be treated as a particular type of molecular distribution. Consider the simplest gas-phase reaction, one in which molecules of A are converted to molecules of B. the reaction, described by the equation Q : Concentration of urea Help me to go Help me to go through this problem. 6.02x 1020 molecules of urea are present in 100 ml of its solution. The concentration of urea solution is: (a) 0.02 M (b) 0.01 M (c) 0.001 M (d) 0.1 M (Avogadro constant, N4= 6.02x 1023mol -1)<
Help me to go through this problem. 6.02x 1020 molecules of urea are present in 100 ml of its solution. The concentration of urea solution is: (a) 0.02 M (b) 0.01 M (c) 0.001 M (d) 0.1 M (Avogadro constant, N4= 6.02x 1023mol -1)<
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