--%>

What is solvent dielectric effect? Explain with equation.

Ionic dissociation depends on the dielectric constant of the solvent.

The Arrhenius that ions are in aqueous solutions in equilibrium with parent molecular species allows many of the properties of ionic solutions to be understood. But difficulties began to arise after the initial acceptance of this ionic solution is to be understood. Ultimately the Arrhenius theory was attacked for the postulating molecules instead of ions in solutions of strong electrolytes. This was a dramatic reversal of the initial attacks on the Arrhenius theory which criticized it for postulating ions instead of undissolved molecules.

Refinements to the simplest ideas of the ionic solutions depend on the recognition of the role of the solvent and on the effect of interactions between the ions. 

A remarkable feature of the Arrhenius electrolytic dissociation theory is that although it attributes the dissociation process to the solution of the electrolyte, it proceeds to ignore the role of the solvent. It treats the solvent as if it were an inert, ignorable medium. A detailed understanding of the molecular nature of ionic solutions must involve the very important role played by the solvent. It is necessary, for instance, to understand why water is a unique solvent for ionic systems.

The electrostatic force of attraction between ions of charge Z+ and Z- is given by Coulomb's law:

For vacuum: ƒ(r) = Z+Z-[e2/4∏ε0)]/r2

For medium of dielectric ε/ε0: ƒ(r) = Z+Z-[e2/4∏ε0)]/(ε/ε0)r2

With the numerical values for e2/4∏ε0, the second of this equation is:

ƒ (r) = (2.307 × 10-28) Z+Z-/(ε/ε0)r2

For water, the dielectric constant factor ε/ε0 has the very large value of about 80. The force of interaction and the energy required to overcome coulombic forces are thus smaller by almost of very low dielectric. The easy dissociation of electrolytes in aqueous solutions compared with gaseous or low phase dielectric material is therefore understandable in terms of the high dielectric constant of water. The initial criticisms raised against the Arrhenius theory for postulating the dissociation of electrolysis in solution, however, remain valid arguments against any theory postulating appreciable dissociation to form free ions insolvents of low dielectric constant.

Although the dielectric effect is a major factor for the formation of ionic species in aqueous solutions, it is not great enough to reduce the intermolecular interaction to the small values found for gas phase molecules. We must therefore produce that for all but extremely dilute solutions, ionic interactions will not produce behavior found at infinite dilutes.

929_solvent dielectric.png 
A similar treatment of the activities themselves leads, again for one to one electrolytes, to the mean activity 1285_solvent dielectric1.png

Extension of this property lets activities and their coefficients be defined for electrolytes beyond the AB type. An AB2 electrolyte would dissociate according to 

AB2 = A2+ + 2B-

And the activity term that would appear in all thermodynamic treatments would be of form:

(aA2+) (aB-)2

   Related Questions in Chemistry

  • Q : Molecular substances what are the most

    what are the most important inorganic molecular substances for living beings?

  • Q : Problem on MM equation How to obtain

    How to obtain relation between Vm and Km,given k(sec^-1) = Vmax/mg of enzyme x molecular weight x 1min/60 sec S* = 4.576(log K -10.753-logT+Ea/4.576T).

  • Q : Molality of a glucose solution What

    What will be the molality of a solution containing 18g of glucose (having mol. wt. = 180) dissolved in 500g of water: (i) 1m  (ii) 0.5m  (iii) 0.2m  (iv) 2m

  • Q : Calculate molarity of a solution

    Provide solution of this question. Molarity of a solution prepared by dissolving 75.5 g of pure KOH in 540 ml solution is: (a) 3.05 M (b) 1.35 M (c) 2.50 M (d) 4.50 M

  • Q : Problem on molality Select the right

    Select the right answer of the question. Calculate the molality of 1 litre solution of 93% H2SO4 (weight/volume). The density of the solution is 1.84 g /ml : (a) 10.43 (b) 20.36 (c) 12.05 (d) 14.05

  • Q : Benzoic acid is weaker than paranitro

    Briefly state that Benzoic acid is weaker than paranitro benzoic acid?

  • Q : Problem on vapour pressure and mole

    Provide solution of this question. The vapour pressure of a solvent decreased by 10 mm of mercury, when a non-volatile solute was added to the solvent. The mole fraction of the solute in the solution is 0.2. What should be the mole fraction of the solvent, if decrea

  • Q : Molarity A solution has volume 200ml

    A solution has volume 200ml and molarity 0.1.if it is diluted 5times then calculate the molarity of reasulying solution and the amount of water added to it.

  • Q : Solution problem What is the correct

    What is the correct answer. To made a solution of concentration of 0.03 g/ml of AgNO3, what quantity of AgNO3 must be added in 60 ml of solution: (a) 1.8  (b) 0.8  (c) 0.18  (d) None of these

  • Q : Utilization of glacial acetic acid What

    What is the utilization of glacial acetic acid? Briefly describe the uses.