--%>

Explain alcohols and phenols in organic chemistry.

Alcohols and phenols are the compounds containing one or more hydroxyl groups (- OH). The alcohols contain the -OH group attached to alkyl group whereas in phenols, the -OH group is attached to aromatic ring. These are classified as mono-, di- and trihydric alcohols or phenols according to the number of -OH groups contained in their molecules. Some examples of mono-, di- and trihydric alcohols and phenols are as follows:

    Alcohols

2399_alcohol and phenol.png 

It may be noted that the aromatic compounds in which -OH group is not directly attached to benzene ring are not phenols but are called aromatic alcohols. These may also be called as aryl derivatives of aliphatic alcohols. When four or more hydroxyl groups are present, they are called polyhydric alcohols or polyhydric phenols.

Monohydric alcohols may be further classified according to the hybrid state of the carbon atom to which the -OH group is attached.
    
Compounds containing Csp3 ) -OH bond

In this type of alcohols, the -OH group is attached to a sp3 hybridised carbon atom. They are further classify as follows:

Primary (1°), secondary (2°) and tertiary (3°) alcohols

Monohydric alcohols are classified as primary, secondary or tertiary alcohols depending upon whether the hydroxyl group is attached to a primary, secondary or tertiary carbon atom. For instance,

1240_alcohol and phenol1.png 

Allylic alcohols: in allylic alcohols, the -OH group is attached to a sp3-hybridised carbon next to the carbon-carbon double bond, that is to an allylic carbon. For instance,

2066_alcohol and phenol2.png 

Benzylic alcohols: in benzlylic alcohols, the -OH group is attached to a sp3 -hybridised carbon atom next to an aromatic ring. Allylic and benzylic alcohols can be secondary, primary or tertiary.
    
Compounds containing Csp3 )-OH bond:

These alcohols include -OH group bonded to a carbon-carbon double bond i.e. to a vinylic carbon or to an aryl carbon. For example, vinylic alcohols and phenols belong to this class of compounds.

   Related Questions in Chemistry

  • Q : P block why BiF3 is ionic whereas other

    why BiF3 is ionic whereas other trihalides are covalent in nature?

  • Q : What are aliphatic amines and its

    In common system, the aliphatic amines are named by using prefix for alkyl group followed by the word amine.In case of mixed amines, the name of alkyl groups are arranged in alphabetical order. This is followed by the word amine. However, for simple secondary or tertiary amines anothe

  • Q : Dissolving Group IV Carbonate Explain

    Explain how dissolving the Group IV carbonate precipitate with 6M CH3COOH, followed by the addition of extra acetic acid.

  • Q : Base parachloroaniline is strong base

    parachloroaniline is strong base than paranitroaniline

  • Q : Utilization of glacial acetic acid What

    What is the utilization of glacial acetic acid? Briefly describe the uses.

  • Q : Mole fraction of hydrogen Give me

    Give me answer of this question. In a mixture of 1 gm H2 and 8 gm O2 , the mole fraction of hydrogen is: (a) 0.667 (b) 0.5 (c) 0.33 (d) None of these

  • Q : Modes of concentration Which of the

    Which of the given modes of expressing concentration is fully independent of temperature: (1) Molarity (2) Molality (3) Formality (4) Normality Choose the right answer from above.

  • Q : Neutralization of sodium hydroxide How

    How much of NaOH is needed to neutralise 1500 cm3 of 0.1N HCl (given = At. wt. of Na =23): (i) 4 g  (ii) 6 g (iii) 40 g  (iv) 60 g

  • Q : Laws of Chemical Combination Laws of

    Laws of Chemical Combination- In order to understand the composition of the compounds, it is necessary to have a theory which accounts for both qualitative and quantitative observations during chem

  • Q : Cations Chromium(III) hydroxide is

    Chromium(III) hydroxide is highly insoluble in distilled water but dissolves readily in either acidic or basic solution. Briefly explain why the compound can dissolve in acidic or in basic but not in neutral solution. Write appropriate equations to support your answer