Einsteins mass energy relation
In Einstein’s mass energy relation e = mc2 for what is c employed or why is light needed for the reactions. As the reactions are with the help of neutrons?
Expert
In this equation c is employed as a speed of light. In chemical reactions most of the reactions are photolytic reaction that signifies bond breaks or formed with the influence of light. Therefore c is employed in the reaction.
Give me answer of this question. An aqueous solution of methanol in water has vapour pressure: (a) Equal to that of water (b) Equal to that of methanol (c) More than that of water (d) Less than that of water
Illustrate the direction of the dipole moment expected for hydrogen bromide?
Which one of the following pairs of solutions can we expect to be isotonic at the same temperature:(i) 0.1M Urea and 0.1M Nacl (ii) 0.1M Urea and 0.2M Mgcl2 (iii) 0.1M Nacl and 0.1M Na2SO4 (iv) 0.1M Ca(NO3<
Liquefied natural gas (LNG) is produced using a Linde liquefaction process from pure methane gas at 3 bar and 280 K (conditions at point 1 in figure below). A three-stage compressor with interceding is used to compress the methane to 100 bar (point 2). The first stage
explain the process of relative lowering of vapour pressure
Explain how dissolving the Group IV carbonate precipitate with 6M CH3COOH, followed by the addition of extra acetic acid, establishes a buffer with a pH of approximately
Determination of correct mol. Mass from Roult's law is applicable to :
Differentiate between the modern periodic table and Mendeleevs table?
Help me to go through this problem. 1000 gms aqueous solution of CaCO3 contains 10 gms of carbonate. Concentration of the solution is : (a)10 ppm (b)100 ppm (c)1000 ppm (d)10000 ppm
Can someone please help me in getting through this problem. Determine the molarity of a solution having 5g of sodium hydroxide in 250ml solution is: (i) 0.5 (ii) 1.0 (iii) 2.0 (d) 0.1Answer: The right answer i
18,76,764
1953992 Asked
3,689
Active Tutors
1413058
Questions Answered
Start Excelling in your courses, Ask an Expert and get answers for your homework and assignments!!