base
parachloroaniline is strong base than paranitroaniline
Choose the right answer from following. Colligative properties are used for the determination of: (a) Molar Mass (b) Equivalent weight (c) Arrangement of molecules (d) Melting point and boiling point (d) Both (a) and (b)  
Provide solution of this question. Which solution will show the maximum vapour pressure at 300 K: (a)1MC12H22O11 (b)1M CH3 COOH (c) 1MNacl2 (d)1MNACl
The following mixture of hydrocarbons is obtained as one stream in a petroleum refinery. Q : What is cannizaro reaction? Explain Aldehydes which do not have -hydrogen atom, such as formaldehyte and benzaldehyte, when heated with concentrated (50%)alkali solutio
Aldehydes which do not have -hydrogen atom, such as formaldehyte and benzaldehyte, when heated with concentrated (50%)alkali solutio
Unit of measurement- These are also some systems for units: (1) C.G.S.
For any symmetric object there is a set of symmetry operations that, together, constitute a mathematical group, called a point group.It is clear from the examples that most molecules have several elements of symmetry. The H2O
brief discription of relative lowering of vapour pressure
When the forces of attraction existing between adsorbate particles and adsorbent almost of the same strength as chemical bonds, the adsorption is called chemical adsorption. This type of adsorption is also known as chemisorptions. Since forces of attraction existing b
Separation by distillation can be described with a boiling point diagram. The important process of distillation can now be investigated. From the boiling point diagram one can see that if a small amount of vapour were removed from a liquid of composit
Mole fraction of any solution is equavalent to: (a) No. of moles of solute/ volume of solution in litter (b) no. of gram equivalent of solute/volume of solution in litters (c) no. of moles of solute/ Mass of solvent in kg (d) no. of moles of any
18,76,764
1922564 Asked
3,689
Active Tutors
1424276
Questions Answered
Start Excelling in your courses, Ask an Expert and get answers for your homework and assignments!!