--%>

Explain structure basicity of amines.

Basic character of amines is related to their structural arrangement. Basic strength of amines depends on the relative ease of formation of the corresponding cation by accepting a proton from the acid. Greater the stability of cation is, more is basic strength of amine.

Alkyl amines Verses Ammonia
    
Alkyl amines are stronger bases than ammonia. This can be explained in terms of electron releasing inductive effect (+I effect) of alkyl groups. Alkyl groups by their electron releasing effect, concentrate electron density on nitrogen and hence, make the lone pair of nitrogen more easily available for sharing with proton. Moreover, electron releasing effect of alkyl groups stabilizes the alkyl ammonia ion formed and hence, shifts the equilibrium in forward direction making the alkylamines stronger bases than ammonia.
1194_Amines.png 
    
Variation of basic strength in primary, secondary and tertiary alkyl amines. Among primary, secondary and tertiary aliphatic amines, the electron releasing effect is maximum in tertiary amines and minimum in primary amines.

The basic strength is expected to increase from primary amine to tertiary amine. The observed basic strength of ethyl amine, diethyl amine and trimethyl amine have been found to follow the expected order in gas phase or in non aqueous solvents like chlorobenzene. However, the order of basicity in aqueous solution does not follow the expected trend and gets altered is revealed by their Kb values.

The actual order of basic strength among 1°, 2°, 3° methyl amines and ethyl amines is as follows:

2327_Amines1.png 

Why order of basic strength gets altered in aqueous medium?

In aqueous medium the basic strength of amines is determined by the stability of the corresponding conjugate acid, or protonated amine i.e. the ammonium ion formed by accepting the proton. The stability of the protonated amine is not only determined by the inductive effect but also by the hydration effect and steric factors.
    
Hydration effect: refers to the stabilization of the protonated amine by the water molecules water molecules form H-bonds with the protonated consequently, greater will be the basic strength of the corresponding amine. The hydration due to H-bonding is maximum in monoalkyl ammonium ion (protonated cation of 1° amine), it is less in dialkyl ammonium ion and still less in trialkyl ammonium ion. Therefore, basic strength should decrease from 1° > 2° > 3°.
    
Steric factors: refer to the crowding of alkyl groups around N atom which causes hindrance to protonation of amine and also cause obstruction to H-bonding of protonated amine. The steric effect obviously increase with the increase in the number of alkyl groups around N atom and consequently the basic strength of amines due to steric factors only should decrease from 1° > 2° > 3°.

The above discussion give us the conclusion that the basic strength of amines can be decided by the overall combined effect of I-effect, hydration effect and steric factors. All these factors favour the highest basic strength of 2° amine.

Now, if alkyl groups are small (such as - CH3 group), then steric hindrance to H-bonding is least. In this case, H-bonding predominates over the stability due to + I effect and therefore, CH3NH2 is more basic than (CH3)3N which corresponds to the observed order.

On the other hand, if alkyl groups are bulkier (-C2H5 and C3H7- etc). There will be considerable steric hindrance to H-bonding. Thus in this case + I effect predominates over stability due to H-bonding. Hence, in this case 3° amine becomes more basic than the 1° amine.

 

 

   Related Questions in Chemistry

  • Q : Problem on preparing of a solution Give

    Give me answer of this question. How many grams of CH3OH should be added to water to prepare 150 solution of@M CH3 OH: (a) 9.6 (b) 2.4 (c) 9.6x 103 (d) 2.4 x103

  • Q : Problem on partial pressure i) Show

    i) Show that the equilibrium constant Kp for the reaction CaCo3(s) ↔ CaO(s) +CO2(g)is about unity (i.e. = 1.0) at 895 °C.ii) If two grams of calcium carbonate are pl

  • Q : Raoults law Give me answer of this

    Give me answer of this question. Provide solution of this question. Which one of the following is the expression of Raoult's law: (a) P-P1/P = n/n+N (b) P1-P/P = N/ N+n (c)P-P2/P1= N/ N-n (d) P1-P/P2= N-n/N

  • Q : Polyhalogen compounds we need 10

    we need 10 examples for the polyhalogen compounds....please help me....need it urgently...

  • Q : Molarity of Sodium hydroxide Select the

    Select the right answer of the question. Molarity of 4% NaOH solution is : (a) 0.1M (b) 0.5M (c) 0.01M (d) 0.05M

  • Q : Problem on mole fraction of glucose

    Provide solution of this question. While 1.80gm glucose dissolve in 90 of H2O , the mole fraction of glucose is: (a) 0.00399 (b) 0.00199 (c) 0.0199 (d) 0.998

  • Q : Effect on vapour pressure of dissolving

    Give me answer of this question. When a substance is dissolved in a solvent the vapour pressure of the solvent is decreased. This results in: (a) An increase in the b.p. of the solution (b) A decrease in the b.p. of the solvent (c) The solution having a higher fr

  • Q : Molar conductance what is the molar

    what is the molar conductance of chloropentaamminecobalt(III) chloride?

  • Q : Calculating Formulae Superphosphate has

    Superphosphate has the formula CaH4(PO4)2 H2O, what is the calculation to get the percentage of Phosphorus, I need to show the calculation. I know it is 30.9737622 u in weight and 2 atoms of the formula, but not sure how to work the calculation backwards.

  • Q : Chemists have not created a periodic

    Explain the reason behind that the chemists have not created a periodic table of compounds?