Introduction:Consideration has been confined to purely resistive feedback circuits and op-amps have been largely taken as ideal, apart from the treatment of a finite CMRR. The other significant practical limitation of op-amps is their finite bandwidth and the related frequency response. Internally, the bandwidth of op-amp is restricted by the consequences of frequency dependent elements of the transistors. The parasitic capacitances present restrict the frequency of operation of individual gain phases.Frequency Response of a Single Inverting Gain phase:The simplified, equivalent, small-signal model of a MOS transistor-based inverting amplifier phase is as shown in figure below. The input resistance is supposed to be very high and is thus omitted from the model. The parasitic capacitive elements have been grouped altogether and appear as single equivalent capacitors at the input, Ci, and output, Co, and as a feedback capacitance, Cf, among output and input of the phase. The amplification is as shown as current source generating an output current controlled by the small-signal trans-conductance, gm.
Figure: Equivalent Circuit of a MOS Transistor Amplifier phase
To find out the frequency dependent gain, the Kirchhoff’s Current Law can be applied to output node taking Vgs1 = Vi. Then:i1 = i2 + i3 + i4(Vi - Vo) j ω Cf = gm1 Vi + (Vo/ro) + Vo j ω Coj ω Cf Vi - gm1 Vi = (Vo/ro) + j ω Co Vo + j ω Cf VoVi (j ω Cf - gm1) = Vo [(1/ro) + (j ω Co) + j ω Cf]Vo/Vi = [j ω Cf - gm1]/[(1/ro) + (j ω Co) + (j ω Cf)]Vo/Vi = [- gm1 {1 – jω(Cf/ gm1)}]/[ (1/ro) + j ω(Co + Cf)]Vo/Vi = (- gm1 ro) [{1 - j ω (Cf/ gm1)}/{1 + j ω (Co + Cf)ro}]
The low frequency gain is as:Vo/Vi| ω →0 = - gm1 roThis is dimensionless and points out the inverting amplification phase. This response is of the general form:Vo/Vi| ω →0 = - gm1 roVo(ω)/Vi(ω) = K[1 – j(ω/ωZ)]/ [1 + j(ω/ωP)] with K = - gm1 roThe numerator has a value of:ωZ = gm1/CfThe denominator has a value of: ωP = 1/( Co + Cf)roIn pole and zero terms, the negative coefficient in numerator points out that the zero is positioned in the right half plane whereas the positive coefficient in the denominator points out that the pole is positioned in the left half plane.Let consider the numerator frequency dependent term:1 – j (ω/ωZ) = |MZ| ∠ΦZ = √1 + (ω/ωZ)2 ∠tan-1 (- ω/ωZ)
The phase and magnitude responses for the numerator term of frequency response are shown plotted in the Bode diagram form as functions of frequency in figure below:
Figure: Magnitude and Phase of numerator term of Frequency Response
Let consider the denominator frequency dependent term:
Bode plots of phase and magnitude of the denominator term of the frequency response is as shown in figure below:
Figure: Magnitude and phase of denominator of Frequency Response
The numerator expression provides a break frequency at ωz and it can be observe that the gain mounts at a rate of 20dB/dec above this frequency, being +3dB if ω = ωz. The phase on the other hand is negative going among 0 and -90o being -45o if ω = ωz. It must be noted that in the Bode approximations, the gain only starts to modify at the break frequency whereas the effect of the phase starts at a decade beneath the break frequency and levels off at a decade above the break frequency. Note as well that the negative phase contributed by the numerator term comes from negative coefficient of the imaginary term. This in turn comes from the feedback, output to input through Cf.
The denominator expression provides a break frequency at ωp and it can be observe that the gain falls off at a rate of -20dB/dec above this frequency, being -3dB if ω = ωp. The phase response on the other hand is similar to that of the numerator term going negative among 0 and -90o being -45o if ω = ωp. The negative phase in this instance is due to the fact that, it is contributed by the denominator inverse term that gives the negative coefficient of the imaginary term whenever rationalised. For typical values of stray capacitances present in a MOS transistor gain stage employed in an op-amp, that is the related values of dc gain and the frequencies of pole and zero are obtained as:gm1ro = 100 ≡ 40 dB; fP = 5.3 MHz; fZ = 3.2 GHz
The phase and magnitude plots for the frequency response of the amplifier phase having such characteristics as shown in figure below, where it can be observe that the pole takes place at a much lower frequency than zero.
Figure: Gain and Phase Response for MOS Transistor Single Gain phase
As the frequency is raised, the first noticeable consequence is the phase shift due to the first pole that starts at a decade beneath the frequency at which this pole is positioned. Once the frequency of the pole is reached the magnitude starts to fall off at a rate of -20dB/decade and the phase reaches -225o, that is, -180o-45o = -225o with the inclusion of inversion in the amplifier. Whenever the frequency reaches ten times that of the pole, then the phase levels off at – 270o, however the magnitude continues to fall. At a frequency of ten times, that at which the zero is positioned, the phase starts to fall further due to the effect of zero. At frequency of zero, the phase reaches – 315o, whereas the magnitude levels off as the rising consequence of the zero cancels the falling result of the pole. At frequency of ten times that of zero the phase reaches its lowest point of – 360o and levels off here. The total phase is asymptotic to -360o.Feedback and Stability:Consider a feed-back amplifier for which the closed loop frequency-dependent gain is provided as:
AV = Vo/Vi = A(ω)/1 + A(ω)βIf A(ω) β >> 1, Vo/Vi → 1/ β
Then the closed loop gain is independent of A(ω).From the stability view point it is the loop gain A(ω)β that is significant. If A(ω)β = - 1 ∠0o or ∠180o then:AV = Vo/Vi = A(ω)/1-1 = A(ω)/0 → ∞This gives mount to instability in that the amplifier becomes self-sustaining needing no input to generate an output. In practice, it begins to oscillate. When β is real and fractional then the amplitude response of loop A(ω)β is simply that of A(ω) scaled down by the factor of β. Phase response of the loop is similar to that of A(ω). In order to make sure stability of the amplifier the feedback loop should be prevented from reaching the condition above. To do this, it should be ensured that the magnitude of the loop gain is less than unity whenever the total loop phase ∠A(ω)β (comprising the inversion via the amplifier) is 0o or 360o. If the amplifier is inverting, this applies to a feedback loop phase shift of 180o.Two-Stage Non-Inverting Amplifier:Consider two phases identical to the prior single phase amplifier placed in cascade and hence the combined gain is non-inverting. This consists of frequency response of the form:Vo(ω)/Vi(ω) = Ao[1 – j(ω/ωZ1)][ 1 – j(ω/ωZ2]/ [1 + j(ω/ωP1)] [1 + j(ω/ωP2)] Where A0 >>1 and ωp1 < ωp2 < ωz1 < ωz2Figure below shows the open-loop response and the feedback-loop response for this amplifier where A0 = 105, β = 0.1 and AV = 10. The pole and zero pair of each individual phase are separated by almost 3 decades; however the zero of the first phase is close to the pole of second phase. This has the effect of arresting the 40dB/dec fall in the gain while raising the slope of the phase characteristic. The consequence of this is that a loop phase of -180o is reached prior to the magnitude of the loop gain and has been decreased to unity, thus allowing instability to take place. This consequence is due to primarily existence of the negative-coefficient zeros in the right half plane. As a result, high gain amplifiers usually necessitate to be compensated, either to make sure that the gain is decreased to unity prior to a phase of -180o being reached, or to lift the phase characteristic and hence the phase of -180o takes place at a higher frequency where the loop gain has fallen under unity. A very simple approach to this is frequently adopted in low and medium grade operational amplifiers by comprising a dominant pole at a very low frequency to guarantee sufficient gain and phase margins. The gain and phase responses of such a compensated amplifier are shown in figure below. The gain and phase margins are measures of how far away the amplifier response is from the boundary of instability and are properly defined below.
Figure: Gain and Phase responses of two-Stage Negative feedback amplifier
Figure: Gain and Phase Responses of a Compensated two Stage amplifier
Gain Margin: It is defined as the difference between the magnitude of loop gain A(ω)β and unity at frequency at which the loop phase is -180o (that is, neglecting the inversion of amplifier).Gain margin = 1/|A(ω)β|∠Φ = -180o ≡ 0- A(ω)β dB|∠Φ = -180oThe design suggestion is that this must be at least 6dBs (a factor of 2) to make sure adequate stability.Phase Margin: It is defined as the difference between the loop phase shift ∠ΦAβ and -180o at frequency at which the loop gain A(ω)β is unity.Phase margin = - 180o - ∠ΦAβ||Aβ| = 1 Where ∠ΦAβ is negative.This is generally quoted as a positive quantity and the design proposal is that this must be at least 30o and is safer whenever greater than 45o to guarantee sufficient stability.Often, manufacturer’s list op-amps as being unity-gain stable. This signifies that full feedback with β = 1 can be applied about the amplifier and stability maintained. Note that beneath such conditions |A(ω)β | = |A(ω)|, the open loop gain of op-amp. Sometimes, though, this condition can’t be satisfied and manufacturers will specify a minimum closed loop gain for op-amp. This is really a manner of specifying the maximum value of β that can be tolerated whereas maintaining stability. This is essential if the open-loop gain |A(ω)|, of the amplifier it is above unity whenever the phase ∠A(ω) is 180o. The feedback network itself can as well be made frequency-dependent and given a phase shift ∠β(ω) to correct the total phase response.
Latest technology based Electrical Engineering Online Tutoring Assistance
Tutors, at the www.tutorsglobe.com, take pledge to provide full satisfaction and assurance in Electrical Engineering help via online tutoring. Students are getting 100% satisfaction by online tutors across the globe. Here you can get homework help for Electrical Engineering, project ideas and tutorials. We provide email based Electrical Engineering help. You can join us to ask queries 24x7 with live, experienced and qualified online tutors specialized in Electrical Engineering. Through Online Tutoring, you would be able to complete your homework or assignments at your home. Tutors at the TutorsGlobe are committed to provide the best quality online tutoring assistance for Electrical Engineering Homework help and assignment help services. They use their experience, as they have solved thousands of the Electrical Engineering assignments, which may help you to solve your complex issues of Electrical Engineering. TutorsGlobe assure for the best quality compliance to your homework. Compromise with quality is not in our dictionary. If we feel that we are not able to provide the homework help as per the deadline or given instruction by the student, we refund the money of the student without any delay.
Gnathostomata tutorial all along with the key concepts of Features of Superclass Gnathostomata, Characteristics of Class Placodermi, Cartilaginous fishes and Features of Class Osteichthyes
Theory and lecture notes of Secant Methods all along with the key concepts of secant methods, Regula Falsi Method, Convergence, Simulations and Experiments. Tutorsglobe offers homework help, assignment help and tutor’s assistance on Secant Methods.
mammalia tutorial all along with the key concepts of features of the mammal, external feature of the rabbit and adaptation to ecological environment
tutorsglobe.com environmental factors assignment help-homework help by online environmental biology tutors
tutorsglobe.com modified accelerated cost recovery system homework help-assignment help by online accounting basics tutors.
tutorsglobe.com nature of coordination compounds assignment help-homework help by online types of salts tutors
Field Theories tutorial all along with the key concepts of Ligand and Crystal Field theory, Valence Bond Theory, Molecular Orbital Theory, Differences between the valence bond and molecular orbital theories and Crystal Field theory
It is an instrument that receives the radio signals from the broad casting stations and produce sound. In year 1895, Marconi achieved in telecommunication that is termed as Radio communication.
tutorsglobe.com definition of a tax assignment help-homework help by online fiscal policy tutors
Theory and lecture notes of Introduction to the chi-square distribution all along with the key concepts of chi-square distribution, Goodness-of-fit Test, Properties of the Chi-Square and Chi-Square Probabilities. Tutorsglobe offers homework help, assignment help and tutor’s assistance on chi-square distribution.
Theory and lecture notes of Interest Rates and Aggregate Demand all along with the key concepts of Interest Rates, Aggregate Demand, Investment as a Share of Real GDP, Importance of Investment. Tutorsglobe offers homework help, assignment help and tutor’s assistance on Interest Rates and Aggregate Demand.
www.tutorsglobe.com offers reactions at the a-carbon homework help, reactions at the a-carbon assignment help, online tutoring assistance, organic chemistry solutions by online qualified tutor's help.
Theory and lecture notes of Media failure logic all along with the key concepts of media failure logic, homework help, assignment help, structure of recovery manager. Tutorsglobe offers homework help, assignment help and tutor’s assistance on Media failure logic.
theory and lecture notes of analysis of ac networks, all along with the key concepts of combined reactances, argand diagram and kirchhoff’s laws. tutorsglobe offers homework help, assignment help and tutor’s assistance on analysis of ac networks.
Gravimetric Analysis of a Soluble Chloride tutorial all along with the key concepts of Safety and laboratory method note, Preparation of Filter Crucibles, Preparation of the Chloride Unknown Samples, Precipitation of Chloride by Silver Ion, Filtration and Final Weighing
1952260
Questions Asked
3689
Tutors
1496457
Questions Answered
Start Excelling in your courses, Ask an Expert and get answers for your homework and assignments!!