--%>

Explain the polymers and its types.

Polymers are the chief products of modern chemical industry which form the backbone of present society. Daily life without the discovery and varied applications of polymers would not have been easier and colourful. The materials made of polymers find multifarious uses and applications in all walks of our life. They have influenced our day to day life to such an extent that it is impossible to get through the day without using a material based on polymers. Common examples of these include plastic dishes, cups, non-stick. Pans, automobile tyres and seat covers, plastic bags, rain coats, plastic pipes and fitting radio, TV and computer cabinets; wide range of synthetic fibres for clothing, synthetic glues, flooring materials and materials for biomedical and surgical operations. 

Word polymer means "many parts" (Greek: poly means many and merors means parts). A polymer is a compound of high molecular mass created by the mixture of large number of small molecules. The small molecules which comprise the repeating units in a polymer are known as monomer units. The process by which the monomers are transformed into polymer is called polymerization. For example, polyethylene is a polymer which is obtained by the polymerization of ethylene. The ethylene molecules are referred to as monomer units.
1000_Polymers.png 
As polymers are single and giant molecules, i.e. big size molecules, they are also known as macromolecules.

Homopolymers and copolymers

Polymers are divided into two broad categories depending upon the nature of the repeating structural units. These are homopolymers and co-polymers.

The polymer formed from one kind of monomer is called homopolymers while polymer formed from more than one kind of monomer units is called copolymer or mixed polymer. For example, polyethylene is an example of homopolymers whereas Buna-S rubber which is formed from 1, 3-butadiene (CH2 = CH - CH = CH2) and styrene (C6H5CH = CH2) is an example of copolymer. 

 

 

 

   Related Questions in Chemistry

  • Q : Haloalkanes define primary secondary

    define primary secondary and tertiary alkyl halides with examples

  • Q : Haloalkane how haloalkane can be

    how haloalkane can be prepared by refluxing alcohol with hydrohalic acids

  • Q : Mole 2.0gram of dolomite is heated to a

    2.0gram of dolomite is heated to a constant weight of 1.0g. Calculate the total volume of CO2 produced at STP by this reation

  • Q : Concentration of Calcium carbonate Help

    Help me to go through this problem. 1000 gms aqueous solution of CaCO3 contains 10 gms of carbonate. Concentration of the solution is : (a)10 ppm (b)100 ppm (c)1000 ppm (d)10000 ppm

  • Q : Problem based on molarity Select the

    Select the right answer of the question. If 18 gm of glucose (C6H12O6) is present in 1000 gm of an aqueous solution of glucose, it is said to be: (a)1 molal (b)1.1 molal (c)0.5 molal (d)0.1 molal

  • Q : Molar and Volumetric flow rate problem

    Cyclohexane (C6H12) is produced by mixing Benzene and hydrogen. A process including a reactor, separator, and recycle stream is used to produce Cyclohexane. The fresh feed contains 260L/min C6H6 with 950 L/min of H2

  • Q : State octet rule in chemistry Explain

    Explain what is octet rule in chemistry?

  • Q : Explain Vapour Pressure Composition A

    A pressure composition diagram for a liquid vapor system can be used to show the composition of the liquid and equilibrium vapor.Vapor equilibrium data are useful in the study of distillations. It is of value to have diagrams showing not only the vapor pre

  • Q : Atmospheric pressure Give me answer of

    Give me answer of this question. The atmospheric pressure is sum of the: (a) Pressure of the biomolecules (b) Vapour pressure of atmospheric constituents (c) Vapour pressure of chemicals and vapour pressure of volatile (d) Pressure created on to atmospheric molecules

  • Q : Strength of the Hydrochloric acid

    Provide solution of this question. 1.0 gm of pure calcium carbonate was found to need 50 ml of dilute HCL for complete reaction. The strength of the HCL solution is specified by : (a) 4 N (b) 2 N (c) 0.4 N (d) 0.2 N