Critical Path in Network Analysis
Basic Scheduling Computations
The notations used are
(i, j) is Activity with tail event i and head event j
Ei is Earliest occurrence time of event i
Lj is Latest allowable occurrence time of event j
Dij is Estimated completion time of activity (i, j)
(Es)ij is Earliest starting time of activity (i, j)
(Ef)ij is Earliest finishing time of activity (i, j)
(Ls)ij is Latest starting time of activity (i, j)
(Lf)ij is Latest finishing time of activity (i, j)
The process is as follows
The calculation commences from the start node and goes towards the end node. For easiness, the forward pass computation begins by assuming the first occurrence time of zero for the first project event.
i. Earliest starting time of activity (i, j) is also the earliest event time of the tail end event, that is (Es)ij = Ei
ii. Earliest finish time of activity (i, j) is also the earliest starting time + the activity time, that is (Ef)ij = (Es)ij + Dij or (Ef)ij = Ei + Dij
iii. Earliest event time for event j is the maximum of the earliest finish times of each and every activities end in to that event, that is Ej = max [(Ef)ij for all immediate predecessor of (i, j)] or Ej =max [Ei + Dij]
For end event suppose E = L. Remember that all E's have been calculated by forward pass computations.
Latest finish time for activity (i, j) is equivalent to the latest event time of event j, that is (Lf)ij = Lj
Latest starting time of activity (i, j) is equal to the latest completion time of (i, j) - the activity time or (Ls)ij =(Lf)ij - Dij or (Ls)ij = Lj - Dij
Latest event time for event 'i' is the least of the latest start time of all activities originating from that event, that is Li = min [(Ls)ij for all immediate successor of (i, j)] = min [(Lf)ij - Dij] = min [Lj - Dij]
There are three types of floats
(Tf)ij = (Latest start - Earliest start) for activity ( i - j)
(Tf)ij = (Ls)ij - (Es)ij or (Tf)ij = (Lj - Dij) - Ei
(Ff)ij = (Earliest time for event j - Earliest time for event i) - Activity time for ( i, j)
(Ff)ij = (Ej - Ei) - Dij
(If)ij = (Ej - Li) - Dij
The negative independent float is always considered as zero.
Head event slack = Lj - Ej, Tail event slack = Li - Ei
Theory and lecture notes on the concept of Frequency Response Considerations all along with the key concepts of Single Inverting Gain phase, Feedback and Stability, Two-Stage Non-Inverting Amplifier, Gain Margin and Phase Margin. Tutorsglobe offers homework help, assignment help and tutor’s assistance on Frequency Response Considerations.
tutorsglobe.com dynamics of filtration assignment help-homework help by online excretion tutors
theory and lecture notes of power in ac circuits iii all along with the key concepts of power factor, impedance, power factor correction, resistance, inductive component and capacitive component. tutorsglobe offers homework help, assignment help and tutor’s assistance on theory of power in ac circuits iii.
theory and lecture notes of exponential and logarithmic functions all along with the key concepts of exponential functions and their graphs, exponential and logarithmic models, properties of logarithms. tutorsglobe offers homework help, assignment help and tutor’s assistance on exponential and logarithmic functions.
tutorsglobe.com extraction of lanthanides assignment help-homework help by online lanthanide series tutors
www.tutorsglobe.com offers Essentials to Successful Budgeting homework help, assignment help, case study, writing homework help, online tutoring assistance by accounting tutors.
Limitations of Job Costing - It is state that it is too time consuming and needs detailed record keeping. This creates the method more expensive.
tutorsglobe.com cultural structures of indigenous people assignment help-homework help by online humanities tutors
Counters tutorial all along with the key concepts of Asynchronous (Ripple) Counter, Operation of ripple counter, Mod of Counter, Frequency Division, Synchronous Counter, Controlled Synchronous Counter, Ring Counter, Mod 10 (Decade) Counter
tutorsglobe.com members of the electron transport chain assignment help-homework help by online electron transport chain tutors
tutorsglobe.com origin and development of plant tissue culture assignment help-homework help by online plant tissue culture tutors
tutorsglobe.com history of medical microbiology assignment help-homework help by online microbiology tutors
www.tutorsglobe.com offers system fundamentals homework help, system fundamentals assignment help, case study, writing homework help, online tutoring assistance by computer science tutors.
Disconnect the supply cables at the motor’s terminal box, separate the motor from the driven machine, detach the foundation bolts or nuts and eliminate the motor to the maintenance shop.
tutorsglobe.com viscosity assignment help-homework help by online cell membrane tutors
Start Excelling in your courses, Ask an Expert and get answers for your homework and assignments!!