--%>

How to calculate solutions molar conductance?

The contribution of an electrolyte, or an ion electrolyte, is reported as the molar of a conductance.


The definition of the molar conductance is based on the following conductivity cell in which the electrodes are 1 m apart and of sufficient area that the cell holds the amount of solution that contains 1 mol of solute. The conductivity of such a cell is the mole conductance.

A of solution of concentration c, expressed in moles per litre, has a volume in litres per mole of 1/c or a volume in cubic meters of (10-3 m3 l-1)/c. a cell with this volume and electrodes separated by 1 m would be equilivalent to (10-3 m3 l-1)/c unit cells placed alongside each other. The conductivity of such a cell, which is the molar conductance, is given by:

A = 10-3 m3 l-1/c × k

This relation defines the molar conductance in terms of the specific conductance. The concept of the cell holding solution of volume (10-3 m3 l-1)/c is introduced only to suggest the definition of conductance and in practice one uses any convenient conductance cell, measures R, and calculate L = 1/R. with this datum one obtains k= (cell constant) L and finally A.

Many precise measurements of molar conductance were made by Friedrich Kohlausch and his coworkers between about 1860 and 1880. 

On the basis of such data and in the absence of any satisfactory theory about the nature of conduction in these solutions, some variable empirical relations were concluded. It was recognized that for some electrolytes plotting the molar conductance of an electrolyte at a fixed temperature against the square root of the concentration led to the plots which confirmed very closely at the lower concentrations to straight lines. Such plots for new electrolytes are lead to essentially linear plots are now classed as strong electrolytes, and those which seem to approach the dilute solution limit almost tangentially are classed as weak electrolytes.

An important relation can be deduced from extrapolations of the strong electrolyte data to infinite dilution to give what are known as limiting molar of the independent migration of ions. The law is more easily stated and understandable if some later ideas are anticipated and the conductance of an electrolyte at infinite dilution is treated as being made of contributions from the individual ions of the electrolyte. Let v+ be the number of positive ions and v - the number of negative ions implied by the formula of the electrolyte. 

Molar conductances ? in Ω-1 m2 mol-1 in aqueous solution at 25° C (values for c = 0obtained by extrapolation or, for HAc and NH4OH, by a combination of extrapolated values):

c NaCl KCl HCl NaAc CuSO4 H2SO4 HAc NH4OH
0.000 (0.012645) 0.014986 0.042616 0.00910 0.02661 0.08592 0.03907 0.002714
0.0005 (0.012450) 0.014781 0.042274 0.00892 0.02304 0.08262 0.00677 0.0047
0.001 0.012374 0.014695 0.042136 0.00885 0.01666 0.07990 0.00492 0.0034
0.010 0.011851 0.014127 0.041200 0.008376 0.01010 0.06728 0.00163 0.00113
0.100 0.010674 0.012896 0.039132 0.007280 0.00586 0.05016   0.00036
1.00   0.01119 0.03328 0.00491        

   Related Questions in Chemistry

  • Q : Utilization of glacial acetic acid What

    What is the utilization of glacial acetic acid? Briefly describe the uses.

  • Q : Numerical The volume of water to be

    The volume of water to be added to 100cm3 of 0.5 N N H2SO4 to get decinormal concentration is : (a) 400 cm3 (b) 500cm3 (c) 450cm3 (d)100cm3

  • Q : Depression in the freezing point When

    When 0.01 mole of sugar is dissolved in 100g of a solvent, the depression in freezing point is 0.40o. When 0.03 mole of glucose is dissolved in 50g of the same solvent, depression in the freezing point will be:(a) 0.60o  (b) 0.80o

  • Q : Moles of chloride ion Select the right

    Select the right answer of the question. A solution of CaCl2 is 0.5 mol litre , then the moles of chloride ion in 500ml will be : (a) 0.25 (b) 0.50 (c) 0.75 (d)1.00

  • Q : Neutralisation of phosphorous acids

    Provide solution of this question. To neutralise completely 20 mL of 0.1 M aqueous solution of phosphorous acid (H3 PO3) the volume of 0.1 M aqueous KOH solution required is: (a) 40 mL (b) 20 mL (c) 10 mL (d) 60 mL

  • Q : The three facts on the evaporation

    Describe briefly the three facts on the evaporation?

  • Q : Solutions The normality of 10 lit.

    The normality of 10 lit. volume hydrogen peroxide is: (a) 0.176 (b) 3.52 (c) 1.78 (d) 0.88 (e)17.8

  • Q : Concentration of an aqueous solution

    Give me answer of this question. The concentration of an aqueous solution of 0.01M CH3OH solution is very nearly equal to which of the following : (a) 0.01%CH3OH (b) 0.1%CH3OH (c) xCH3OH= 0.01 (d) 0.99MH2O (

  • Q : Finding Active mass of urea Can someone

    Can someone please help me in getting through this problem. 10 litre solution of urea comprises of 240 gm urea. The active mass of urea is: (i) 0.04 (ii) 0.02 (iii) 0.4 (iv) 0.2

  • Q : Procedure to judge that organic

    Describe briefly the procedure to judge that the given organic compound is pure or not?