--%>

Explain Ionic Bond with examples.

The bonding in ionic molecules can be described with a coulombic attractive term.

For some diatomic molecules we take quite a different approach from that used in preceding sections to describe the bonding. Ionic bonds are interpreted in terms of the coulombic attraction between ions. Since the electronic details of these ions are not dealt with the approach does not require quantum mechanical calculations. The treatment is easier but, as you will see, less satisfying than those in which a complete quantum mechanical description is set up and, with various recognized simplifications, solved.

Let us consider, to be specific, the NaCl molecule. The molecule exists in the high temperature vapour, and its bonding energy and equilibrium bond length and some features of its energy versus internuclear distance curve are known. These are shown by the solid curve of the products of dissociation of an NaCl molecule are the gas phase Na and Cl atoms.

Now let us attempt to develop an energy intermolecular distance curve by using the internuclear model. The energy required converting Na atoms to Na+ ions and Cl atoms to Cl- ions, all in the gas state, can be calculated from ionization:

Na 2118_First order reactions1.png Na = + e         ?U = =495 kJ mol-1

Cl + e- 2118_First order reactions1.png Cl-              ?U = - 349 KJ mol-1

And thus,

Na = Cl 2118_First order reactions1.png Na+ + Cl-    ?U = + 146 KJ mol-1

Infinitely separated gas phase Na and Cl ions lie at an energy 147 KJ mol-1 higher than separateNa and Cl atoms.

As Na+ and Clions approach each other, the potential energy becomes more negative. If we treat the ions at point charges, this potential energy is given by the coulombic term:

Ucoul = - e2/ (4∏e0)/ r

Where r is the internuclear distance, a curve for this function, based on the energies of separateNa+ and Cl- ions has been added.

An opposing effect exists in the form of repulsion between the nuclei, each with its closed shell of electrons. This repulsion term cannot easily be deduced, and it is satisfactory here to use an empirical expression to represent the repulsion that sets in at small internuclear distances. The variation of this repulsive energy contribution with internuclear distance is satisfactorily represented by an empirical equation of the form:

Urep = be-r/p, where p and b are empirical constants.

Furthermore, to a quite good approximation, the constant p can be taken to be the same for all ionic molecules and equal to 0.30 × 10 -10 m = 30 pm. Thus,

Urep = be -r/(0.30 × 10-10)

The total potential energy can now be written as:

U = - e2/(4∏e0)/r + be -r/(0.30 × 10-10)


The value of the remaining empirical constant b can be deduced by requiring U to have a minimum at the experimentally determined equilibrium bond length. Setting the derivate equal to zero for r = 2.36 × 10-10 m, the equilibrium bond length for NaCl, gives b = 1.95 × 105 kJmol-1. Substitution of the numerical value e2/(4∏eo) and expressing r in picometers gives:

U(kJ mol-1) = - 138,900/r + 195,000e-r/30 (r in picometers)


Calculated dissociation energy = 514 - 146 = 368 KJ mol-1

The result can be compared with the experiment value of 406 kJ mol-1

The attraction energy curve, the repulsion energy curve, and the total energy curve are the ionic model describes the system satisfactorily up to an internuclear separation of about 100 pm. Then the bond description must changes so that at complete separation the products released from each other are atoms rather than ions. 

   Related Questions in Chemistry

  • Q : Explain solid in liquid solutions. The

    The French chemist Francois Marie Raoult (1886) carried out a series of experiments to study the vapour pressure of a number of binary solutions. On the basis of the results of the experiments, he proposed a generalization called Raoult's law which states that, <

  • Q : Chem Explain how dissolving the Group

    Explain how dissolving the Group IV carbonate precipitate with 6M CH3COOH, followed by the addition of extra acetic acid.

  • Q : Isotonic Solutions Which one of the

    Which one of the following pairs of solutions can we expect to be isotonic at the same temperature:(i) 0.1M Urea and 0.1M Nacl  (ii) 0.1M Urea and 0.2M Mgcl2  (iii) 0.1M Nacl and 0.1M Na2SO4  (iv) 0.1M Ca(NO3<

  • Q : Question on Raoults law Give me answer

    Give me answer of this question. For a dilute solution, Raoult's law states that: (a) The lowering of vapour pressure is equal to mole fraction of solute (b) The relative lowering of vapour pressure is equal to mole fraction of solute (c) The relative lowering of v

  • Q : Biodegradable polymers what are the

    what are the examples of biodegradable polymers

  • Q : Question based on strength of solution

    Help me to go through this problem. On dissolving 1 mole of each of the following acids in 1 litre water, the acid which does not give a solution of strength 1N is: (a) HCl (b) Perchloric acid (c) HNO3 (d) Phosphoric acid

  • Q : Molarity 20mol of hcl solution requires

    20mol of hcl solution requires 19.85ml of 0.01 M NAOH solution for complete neutralisation. the molarity of hcl solution

  • Q : Raoults law Give me answer of this

    Give me answer of this question. Provide solution of this question. Which one of the following is the expression of Raoult's law: (a) P-P1/P = n/n+N (b) P1-P/P = N/ N+n (c)P-P2/P1= N/ N-n (d) P1-P/P2= N-n/N

  • Q : Calculation of concentration of the

    Choose the right answer from following. 200ml of a solution contains 5.85 dissolved sodium chloride. The concentration of the solution will be(Na= 23: cl = 35.5 ) (a) 1 molar (b) 2 molar (c) 0.5 molar (d) 0.25 molar

  • Q : Group Cations Explain how dissolving

    Explain how dissolving the Group IV carbonate precipitate with 6M CH3COOH, followed by the addition of extra acetic acid, establishes a buffer with a pH of approximately