--%>

Explain Ionic Bond with examples.

The bonding in ionic molecules can be described with a coulombic attractive term.

For some diatomic molecules we take quite a different approach from that used in preceding sections to describe the bonding. Ionic bonds are interpreted in terms of the coulombic attraction between ions. Since the electronic details of these ions are not dealt with the approach does not require quantum mechanical calculations. The treatment is easier but, as you will see, less satisfying than those in which a complete quantum mechanical description is set up and, with various recognized simplifications, solved.

Let us consider, to be specific, the NaCl molecule. The molecule exists in the high temperature vapour, and its bonding energy and equilibrium bond length and some features of its energy versus internuclear distance curve are known. These are shown by the solid curve of the products of dissociation of an NaCl molecule are the gas phase Na and Cl atoms.

Now let us attempt to develop an energy intermolecular distance curve by using the internuclear model. The energy required converting Na atoms to Na+ ions and Cl atoms to Cl- ions, all in the gas state, can be calculated from ionization:

Na 2118_First order reactions1.png Na = + e         ?U = =495 kJ mol-1

Cl + e- 2118_First order reactions1.png Cl-              ?U = - 349 KJ mol-1

And thus,

Na = Cl 2118_First order reactions1.png Na+ + Cl-    ?U = + 146 KJ mol-1

Infinitely separated gas phase Na and Cl ions lie at an energy 147 KJ mol-1 higher than separateNa and Cl atoms.

As Na+ and Clions approach each other, the potential energy becomes more negative. If we treat the ions at point charges, this potential energy is given by the coulombic term:

Ucoul = - e2/ (4∏e0)/ r

Where r is the internuclear distance, a curve for this function, based on the energies of separateNa+ and Cl- ions has been added.

An opposing effect exists in the form of repulsion between the nuclei, each with its closed shell of electrons. This repulsion term cannot easily be deduced, and it is satisfactory here to use an empirical expression to represent the repulsion that sets in at small internuclear distances. The variation of this repulsive energy contribution with internuclear distance is satisfactorily represented by an empirical equation of the form:

Urep = be-r/p, where p and b are empirical constants.

Furthermore, to a quite good approximation, the constant p can be taken to be the same for all ionic molecules and equal to 0.30 × 10 -10 m = 30 pm. Thus,

Urep = be -r/(0.30 × 10-10)

The total potential energy can now be written as:

U = - e2/(4∏e0)/r + be -r/(0.30 × 10-10)


The value of the remaining empirical constant b can be deduced by requiring U to have a minimum at the experimentally determined equilibrium bond length. Setting the derivate equal to zero for r = 2.36 × 10-10 m, the equilibrium bond length for NaCl, gives b = 1.95 × 105 kJmol-1. Substitution of the numerical value e2/(4∏eo) and expressing r in picometers gives:

U(kJ mol-1) = - 138,900/r + 195,000e-r/30 (r in picometers)


Calculated dissociation energy = 514 - 146 = 368 KJ mol-1

The result can be compared with the experiment value of 406 kJ mol-1

The attraction energy curve, the repulsion energy curve, and the total energy curve are the ionic model describes the system satisfactorily up to an internuclear separation of about 100 pm. Then the bond description must changes so that at complete separation the products released from each other are atoms rather than ions. 

   Related Questions in Chemistry

  • Q : Molecular weight of substance The

    The boiling point of a solution of 0.11 gm of a substance in 15 gm of ether was found to be 0.1oC higher than that of the pure ether. The molecular weight of the substance will be (Kb = 2.16)       (a) 148 &nbs

  • Q : Structure of a DNA molecule Elaborate

    Elaborate the structure of a DNA molecule?

  • Q : Determining concentration in ppm A 500

    A 500 gm tooth paste sample has 0.2g fluoride concentration. Determine the concentration of F in terms of ppm level: (a) 250 (b) 200 (c) 400 (d) 1000Answer: (c) F-ions in ppm = (0.2/500) x 106 = 400

  • Q : Calculating total vapour pressure

    Select the right answer of the question. The vapour pressure of two liquids P and Q are 80 and 600 torr, respectively. The total vapour pressure of solution obtained by mixing 3 mole of P and 2 mole of Q would be: (a) 140 torr (b) 20 torr (c) 68 torr (d) 72 torr

  • Q : Molecular Structure type The ionic

    The ionic radii of Rb+ and I- respectively are 1.46 Å and 2.16Å. The very most probable type of structure exhibited by it is: (a) CsCl type  (b) ZnS type  (c) Nacl type  (d) CaF2 type

    Q : Calculation of molecular weight Provide

    Provide solution of this question. In an experiment, 1 g of a non-volatile solute was dissolved in 100 g of acetone (mol. mass = 58) at 298K. The vapour pressure of the solution was found to be 192.5 mm Hg. The molecular weight of the solute is (vapour pressure of ace

  • Q : What are haloalkanes and haloarenes and

    Alkyl halides or haloalkanes are the compounds in which a halogen is bonded to an alkyl group. They have the general formula RX (where R is alkyl grou

  • Q : What is covalent radii? Explain its

    Average covalent radii can be assigned on the basis of molecular structures. The accumulation of structural data by spectroscopic studies and both electron and x-ray diffraction studies allows one to investigate the possibili

  • Q : How molecule-molecule collisions takes

    An extension of the kinetic molecular theory of gases recognizes that molecules have an appreciable size and deals with molecule-molecule collisions. We begin studies of elementary reactions by investigating the collisions b

  • Q : Preparation of ammonium sulphate Select

    Select the right answer of the question. Essential quantity of ammonium sulphate taken for preparation of 1 molar solution in 2 litres is: (a)132gm (b)264gm (c) 198gm (d) 212gm