Determining mole fraction of water in mixture
A mixture has 18 g water and 414 g ethanol. What is the mole fraction of water in mixture (suppose ideal behaviour of mixture): (i) 0.1 (ii) 0.4 (iii) 0.7 (iv) 0.9 Choose the right answer from above.
A mixture has 18 g water and 414 g ethanol. What is the mole fraction of water in mixture (suppose ideal behaviour of mixture): (i) 0.1 (ii) 0.4 (iii) 0.7 (iv) 0.9
Choose the right answer from above.
Expert
The right answer is (a) Molecular weight of C2H5OH = 24+5+16+1= 46Molecular mass of H2O = 18414g of C2H5OH has 414/ 46= 9 mole18g H2O has 18/18 = 1 moleMole fraction of water = n1/ n1 + n1 = 1 / 1+9 = 1 / 10 = 0.1
what is the relationship between vitamins and enzyme cofactors
Help me to solve this problem. 0.5 M of H2AO4 is diluted from 1 lire to 10 litre, normality of resulting solution is : (a)1 N (b) 0.1 N (c)10 N (d)11 N
What volume of solution contains 0.1 mole of the solute: (a) 100ml (b) 125ml (c) 500ml (d) 62.5ml Choose the right answer from above.
If 20ml of 0.4N, NaoH solution completely neutralises 40ml of a dibasic acid. The molarity of the acid solution is: (a) 0.1M (b) 0.2M (c) 0.3M (d) 0.4M Choose the right answer fron above.
Provide solution of this question. The weight of sodium carbonate required to prepare 500 ml of a seminormal solution is: (a) 13.25 g (b) 26.5 g (c) 53 g (d) 6.125 g
why pentahalids are more covalent than tetrahalids
Briefly describe the properties of the carbohydrates?
Presence of small concentrations of appropriate electrolyte is necessary to stabilize the colloidal solutions. However, if the electrolytes are present in higher concentration, then the ions of the electrolyte neutralize the charge on the colloidal particles may unite
Avogadro's hypothesis Law Principle- Berzelius, a chemist tried
Provide solution of this question. Which solution will show the maximum vapour pressure at 300 K: (a)1MC12H22O11 (b)1M CH3 COOH (c) 1MNacl2 (d)1MNACl
18,76,764
1957329 Asked
3,689
Active Tutors
1421975
Questions Answered
Start Excelling in your courses, Ask an Expert and get answers for your homework and assignments!!