- +1-530-264-8006
- info@tutorsglobe.com

18,76,764

Questions

Asked

21,311

Experts

9,67,568

Questions

Answered

Start Excelling in your courses, Ask an Expert and get answers for your homework and assignments!!

Submit Assignment
## Secant Methods and Regula Falsi Method

Secant Methods:In this lecture we introduce two additional methods to search numerical solutions of the equation f(x) = 0. Both of these methods are basis on approximating the function by secant lines now as Newton’s method was based on approximating the function by tangent lines.

:The Secant MethodThe secant method requires two initial points x

_{0}with x_{1}which are both reasonably close to the solution x*. Preferably the signs of y_{0}= f(x_{0}) and y_{1}= f(x_{1}) must be different. Once x_{0}also x_{1}are determined the method proceeds by the following formula:x

_{i+1 }= x_{i}– [{x_{i}− x_{i−1}}/{y_{i}− y_{i−1}}]*[y_{i}− y_{i−1}]Illustration - Suppose f(x) = x

^{4}− 5 for which the true solution is x*= 4√ 5. Plotting this function disclose that the solution is at about 1.25. If we let x_{0}= 1 as well as x_{1}= 2 then we know that the root is in between x_{0}as well as x_{1}. After that we have that y_{0}= f(1) = −4 and y_{1}= f(2) = 11. We may then compute x_{2}from the formula:Pluggin x

_{2}= 19/15 into f(x) we acquire y_{2}= f(19/15) ≈ −2.425758.... In the subsequent step we would use x_{1}= 2 and x_{2}= 19/15 in the above formula to find x_{3}and so on.Given Below is a program for the secant method. Notice that it necessitate two input guesses x

_{0}and x_{1}, however it does not require the derivative to be input.function x = mysecant(f,x0,x1,n)format long % prints more digits

format compact % makes the output more compact

% Solves f(x) = 0 by doing n steps of the secant method starting with x0 and x1.

% Inputs: f -- the function input as an inline function

% x0 -- starting guess, a number

% x1 -- second starting geuss

% n -- the number of steps to do

% Output: x -- the approximate solution

y0 = f(x0);

y1 = f(x1);

for i = 1:n % Do n times

x = x1 - (x1-x0)*y1/(y1-y0) % secant formula.

y=f(x) % y value at the new approximate solution.

% Move numbers to get ready for the next step

x0=x1;

y0=y1;

x1=x;

y1=y;

end

:The Regula Falsi MethodThe Regula Falsi method is fairly a combination of the secant method and bisection method. The idea is to utilize secant lines to approximate f(x) but choose how to update using the sign of f(xn). Now as in the bisection method we begin with a and b for which f(a) and f(b) have different signs.

Then let:

x = b –[{b – a}/{f(b) − f(a)}]*[f(b)].

Then check the sign of f(x). If it is the similar as the sign of f(a) then x becomes the new a Otherwise let b = x.

Convergence:If we can start with a good choice x0 then Newton’s method will converge to x* rapidly. The secant method is a slightly slower than Newton’s method and the Regula Falsi method is slightly slower than that. Both nevertheless are still much faster than the bisection method.

If we don’t have a good starting point or interval, after that the secant method, just similar to Newton’s method can fail altogether. The Regula Falsi method just similar to the bisection method always works for the reason that it keeps the solution inside a definite interval.

:Simulations and ExperimentsAlthough Newton’s method converges quicker than any other method there are contexts when it isn’t convenient or even impossible. One noticeable situation is when it is difficult to calculate a formula for f′(x) even though one knows the formula for f(x). This is habitually the case when f(x) isn’t defined explicitly however implicitly. There are other situations, which are extremely common in engineering and science where even a formula for f(x) isn’t known. This happens when f(x) is the result of experiment or else simulation rather than a formula. In such circumstances the secant method is usually the best choice.

Latest technology based Matlab Programming Online Tutoring AssistanceTutors, at the

www.tutorsglobe.com, take pledge to provide full satisfaction and assurance inMatlab Programming helpviaonline tutoring. Students are getting 100% satisfaction byonline tutorsacross the globe. Here you can get homework help for Matlab Programming, project ideas and tutorials. We provide email basedMatlab Programming help. You can join us to ask queries 24x7 with live, experienced and qualified online tutors specialized in Matlab Programming. ThroughOnline Tutoring, you would be able to complete your homework or assignments at your home. Tutors at theTutorsGlobeare committed to provide the best qualityonline tutoringassistance forMatlab Programming Homework helpandassignment helpservices. They use their experience, as they have solved thousands of the Matlab Programming assignments, which may help you to solve your complex issues of Matlab Programming.TutorsGlobeassure for the best quality compliance to your homework. Compromise with quality is not in our dictionary. If we feel that we are not able to provide thehomework helpas per the deadline or given instruction by the student, we refund the money of the student without any delay.