Whether HCl is a base or an acid
Whether HCl is a base or an acid? Briefly state your comments?
Expert
HCl or hydrochloric acid, as the name entails, is an acid. However, it is considered a strong acid as it dissociates totally in water to form the H3O+ and Cl-.
Though, it can as well act as a base in reactions with acids stronger than it can similar to HClO4.
Choose the right answer from following. The molar solution of sulphuric acid is equal to: (a) N solution (b) 2Nsolution (c) N/2solution (d) 3Nsolution
order of decreasing basicity of urea and its substituents
What is the correct answer. Which of the given solutions contains highest normality: (i) 8 gm of KOH/litre (ii) N phosphoric acid (iii) 6 gm of NaOH /100 ml (iv) 0.5M H2SO4
Differentiate between the modern periodic table and Mendeleevs table?
The objective of this work is to separate a binary mixture and to cool down the bottom product for storage. (Check table below to see which mixture you are asked to study). 100 kmol of feed containing 10 mol percent of the lighter component enters a continuous distillation column at the m
Provide solution of this question. 1.0 gm of pure calcium carbonate was found to need 50 ml of dilute HCL for complete reaction. The strength of the HCL solution is specified by : (a) 4 N (b) 2 N (c) 0.4 N (d) 0.2 N
Provide solution of this question. The vapour pressure of a solvent decreased by 10 mm of mercury, when a non-volatile solute was added to the solvent. The mole fraction of the solute in the solution is 0.2. What should be the mole fraction of the solvent, if decrea
Show the organic structure of cetearyl alcohol and state what the organic family is? Briefly state it.
are halides are halogens more soluble? why?
Cyclohexane (C6H12) is produced by mixing Benzene and hydrogen. A process including a reactor, separator, and recycle stream is used to produce Cyclohexane. The fresh feed contains 260L/min C6H6 with 950 L/min of H2
18,76,764
1936977 Asked
3,689
Active Tutors
1454812
Questions Answered
Start Excelling in your courses, Ask an Expert and get answers for your homework and assignments!!