Moles of HCl present in .70 L of a .33 M HCl solution

Question

Detail the moles of HCl which are present in .70 L of a .33 M HCl solution?

Answer 1

- Firstly, think of definition of moles (M), M = moles of species / L.
0.33 M = 0.33 moles HCl / L
- Now, multiple your volume by molar concentration:
0.33 moles HCl / L x 0.70 L = 0.231 moles HCl
It is helpful to convey the units with the calculations. In that way we can check ,the  numerators and denominators cancel to give us the units of our answer.