Anti-aromatic and the non-aromatic compounds
What is main difference among anti-aromatic and the non-aromatic compounds?
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The anti aromatic compounds follows 4npi electron rule and are planar, cyclic compounds, while non aromatic are cyclic or acyclic and non-planar or planar.
What do you mean by the term enzymes? Briefly illustrate it.
Give me answer of this question. What is the volume of 0.1NHcl required to react completely with 1.0g of pure calcium carbonate : (Ca= 40, C= 12 and o = 16 ) (a)150cm3 (b)250cm3 (c)200cm3 (d)100cm3 Q : How to calculate solutions molar The contribution of an electrolyte, or an ion electrolyte, is reported as the molar of a conductance. The definition of the molar conductance is based on the following conductivity cell in which the electrodes are 1 m apart and of sufficient area that th
The contribution of an electrolyte, or an ion electrolyte, is reported as the molar of a conductance. The definition of the molar conductance is based on the following conductivity cell in which the electrodes are 1 m apart and of sufficient area that th
The constant of vander Waal's equation can be related to the coefficients of the virial equation. Vander Waal's equation provides a good overall description of the real gas PVT behaviour. Now let us
Common system According to this system, the individual members are named according to alkyl groups att
what is the molarity of the solution prepared by dissolving 75.5 g of pure KOH in 540 ml of solution
The process of adsorption can occurs in solutions also. This implies that the solid surfaces can also adsorb solutes from solutions. Some clarifying examples are listed below: (i) When an aqueous solution of ethano
arrange in decreasing order of basicity pi pyridine,pyridine,pyrrole, morphine
If 20ml of 0.4N, NaoH solution completely neutralises 40ml of a dibasic acid. The molarity of the acid solution is: (a) 0.1M (b) 0.2M (c) 0.3M (d) 0.4M Choose the right answer fron above.
Provide solution of this question. To neutralise completely 20 mL of 0.1 M aqueous solution of phosphorous acid (H3 PO3) the volume of 0.1 M aqueous KOH solution required is: (a) 40 mL (b) 20 mL (c) 10 mL (d) 60 mL
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