You stand at the edge of a cliff holding a ball out over


Compute all parts of following question:

Question: You stand at the edge of a cliff, holding a ball out over the edge. You give the ball an initial velocity of 6.00 m/s straight up, releasing the ball when it is 25.0 m above ground level (the level of the ground at the base of the cliff). Use g = 10.0 m/s2, and neglect air resistance.

Part A: When the ball reaches maximum height, how high above ground level is it?

Part B: How much time passes between the instant you release the ball and the instant the ball reaches ground level?

Part C: What is the ball's speed just before impact with the ground?

I want you to explain the physics in this question.

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Physics: You stand at the edge of a cliff holding a ball out over
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