.387g of NH4Cl was dissolved in 100 ml of distilled water and then titrated with 0.5M of NaOH. At equivalence, the volume of NaOH used was 16.39ml and the pH was 10.44.
1) Use stoichiometry and the balanced reaction below to calculate to moles of NaOH added at the equivalence point from the mass of ammonium chloride used.
NH4Cl + NaOH-->NaCl + H2O + NH3
2) From the moles of NaOH added at equivalence and the volume of NaOH solution added at equivalence, calculate a precise concentration for the NaOH solution.
3) Determine the pKa and Ka of the ammonium chloride from the pH at half-eqivalence.