Let the fourmula for the hydrous copper sulphate be


Let the fourmula for the hydrous copper sulphate be CuSO4XH20 where X represents the number of water molecules. If the mass of the blue copper sulphate crystals is 49,9g before heating and the mass of anhydrous copper sulphate after heating is 31,9g, what ass of water was released during heating?

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Chemistry: Let the fourmula for the hydrous copper sulphate be
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