Unpoloarized light is passed through a set of n polarizers


Unpoloarized light is passed through a set of n polarizers. The first polarizer is arranged with the polarizing slits aligned vertically, and the last polarizer of the set is arranged so its slits are aligned horizontally. Each polarizer in between these 2 polarizers is arranged with its polarizing slits at an angle of ? with respect to the previous one. (In other words, the second polarizer in the set is at an angle of ? with the vertical, the third polarizer is at an angle of 2? with the vertical, the fourth one is at an angle of 3? with the vertical and so forth.) How many total polarizers are required (n = ?) so that the intensity of the light coming out of the last polarizer is 33% of the intensity of light coming into the first polarizer? (Hint: It shouldn’t be too difficult to write a single equation with only the variable ‘n’ in it. This is a transcendental equation and can’t be solved without the use of computers. So, it might be easiest to solve the problem by trial and error. Simply substitute integer values for n into the equation you have, (start with 2 or 3 and work upwards) and find the one that makes the equation true.)

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Physics: Unpoloarized light is passed through a set of n polarizers
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