The standard enthalpy of formation of h2ol at 298 k is 2858


The standard enthalpy of formation of H2O(l) at 298 K is 285.8 kJ/mol. Calculate the change in internal energy for the following process at 298 K and 1 atm: H2O(l) yields H2(g)+12 O2(g); delta E= ? (Hint: Using the ideal gas equation, derive an expression for work in terms of n, R, and T.) Show your work and explain how you arrived at the answer.

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Chemical Engineering: The standard enthalpy of formation of h2ol at 298 k is 2858
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