Standard normal pdf
Let Z have the standard normal pdf fZ(z) =( 1/root(2pi))*e^((-z^2)/2), from - infinity < z < infinity
find the pdf of X=z^2
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Let Z have the standard normal pdf fZ(z) =( 1/root(2pi))*e^((-z^2)/2), from - infinity < z < infinity. Find the pdf of X=z^2
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