Q. A capacitor of capacitance 2 μF is in an ac circuit of frequency 1000 Hz. If the rms value of the applied emf is 10 V, find the effective current flowing through the circuit.
Solution:
Capacitive reactance XC = 1 / ωC
= 1 / 2π ν C
= 1 / 2 X 3.14 X 1000 X 2 X 10 -6
= 79.6 Ω
Irms = E eff / XC
= 10 / 79.6 = 0.126 A