If 620 ml of h2 and 620 ml of ethylene c2h4 are allowed to


If 62.0 mL of H2 and 62.0 mL of ethylene (C2H4) are allowed to react at 1.5 atm, the product ethane (C2H6) has a volume of 62.0 mL. Calculate the amount of PV work done, and tell the direction of the energy flow. C2H4(g) + H2(g) --> C2H6(g)

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Chemistry: If 620 ml of h2 and 620 ml of ethylene c2h4 are allowed to
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