How many moles of bcl3 are needed to produce 25.0 g of hcl


How many moles of BCl3 are needed to produce 25.0 g of HCl(aq) in the following reaction?
BCl3(g) + 3 H2O(l) → 3 HCl(aq) + B(OH)3(aq)

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Chemistry: How many moles of bcl3 are needed to produce 25.0 g of hcl
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