Assume you shoot the arrow straight up at the speed of 60 miles per hour when it leaves bow. From laws of physics it is possible to reduce that t seconds after leaving bow height of arrow from ground (in feet) is:
h = -16t2 + 88t + 7
i. How fast is sixty miles per hour in feet per second?
ii. How high is arrow two seconds after being shot?
iii. About how high arrow goes before it begins falling back to earth?
iv. When it hits ground?