Find the volume of the solid region which lies under the

Question

1. Find the volume of the solid region which lies under the surface z = x²y and which lies over the parallelogram with vertices (0,0), (0,1), (6,0), and (6,1).

2. Compute

_½∫¹ _√(1-x2)∫^x√3 (x² + y²) dy dx + _½∫¹ _√(1-x2)∫^x√3 (x² + y²) dy dx + ₂∫⁴ ₀₎∫^{√(16-x^2)} (x² + y²) dy dx.