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F xi 2yj 3zk and s is a square of side 2 in the plane y


Question: Calculate the flux of the vector field through the surface.

1. F→ = xi→ + 2yj→ + 3zk→ and S is a square of side 2 in the plane y = 3, oriented in the positive y-direction.

2. F→ = 7i→ +6j→ +5k→ and S is a sphere of radius π centered at the origin.

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Mathematics: F xi 2yj 3zk and s is a square of side 2 in the plane y
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