F xi 2yj 3zk and s is a square of side 2 in the plane y


Question: Calculate the flux of the vector field through the surface.

1. F = xi + 2yj + 3zk and S is a square of side 2 in the plane y = 3, oriented in the positive y-direction.

2. F = 7i +6j +5k and S is a sphere of radius π centered at the origin.

Solution Preview :

Prepared by a verified Expert
Mathematics: F xi 2yj 3zk and s is a square of side 2 in the plane y
Reference No:- TGS02410358

Now Priced at $20 (50% Discount)

Recommended (96%)

Rated (4.8/5)