Determine the critical values of the test statistic


Assignment:

Q1. The manager of a driving school claims that the mean time taken to learn how to drive a car is 8 hours or less for all new drivers. A sample of 16 new drivers showed that the mean time taken by them to learn how to drive the car is 9.5 hours with a standard deviation of 1.5 hours. Test the manager's claim at the 1% significance level.

a. Select the null and alternate hypothesis.

1. Ho: µ = 8 H1: µ ≠ 8

2. Ho: µ = 9.5 H1: µ ≠9.5

3. Ho: µ = 8, H1: µ > 8

4. Ho: µ = 9.5, H1: µ > 9.5

b. Determine the critical values of the test statistic.

1. Reject if Z (obs) < Z (o.o1) = - 2.33

2. Reject if Z (obs) > Z (o.01) = 2.33

3 Reject if t (obs) < t (o.o1) = - 2.60

4. Reject if t (obs) > t (o.01) = 2.60

c. Which equation listed below would you use?

1. z = (x bar - µ) / s/vn

2. z = (p - p) / v p (1-p) / n

3. t= (x bar - µ) / s/vn

d. Using the statistical calculator or manual calculation what is the observed statistic and what is your decision regarding the null hypothesis. Provide a one sentence answer.

Q2. A department store manager claims that at least 45% of persons who visited this store make a purchase. In a sample of 400 persons who visited the store 150 made a purchase. Test the manager's claim at the 3% significance level.

a. State the null and alternate hypothesis.
1. Ho: p = 0.45, H1: p ? 0.45

2. Ho: p = 0.45, H1: p < 0.45

3. Ho: p > 0.45, H1: p = 0.45

4. Ho: p = 0.45, H1: p > 0.45

b. Determine the rejection region for the decision rule.

1. Reject if Z (obs) < Z (o.o3) = - 1.88

2. Reject if Z (obs) > Z (o.15) = 2.17

3 Reject if Z (obs) < Z (o.15) = - 2.17

4. Reject if Z (obs) > Z (o.03) = 1.88

c. Which equation listed below would you use?

1. z = (x bar - µ) / s/vn

2. z= (p - p) / v p (1-p) / n

3.t= (x bar - µ) / s/vn

d. Using the statistical calculator or manual calculation what is the observed statistic and what is your decision regarding the null hypothesis. Provide a one sentence answer.

Q3. Complete the ANOVA summary table shown here.

Source of Variation

Sum of Squares

Degrees of freedom

Mean Square

F observed

Between Treatments

 

150.2

 

9

 

 

Error (Within Treatments)

 

200.7

 

 

 

Sums of Squares of Total

 

 

39

 

 

a. How many treatments are there?

b. What is the total sample size?

c. Is there a significant difference at the 5% Level of significance? Would I accept or reject the null Hypothesis. i.e. what is the critical value of the test statistic

d. Select one of the following.

1. There is a significant difference between the treatments

2. There is no significant difference between the treatments

Solution Preview :

Prepared by a verified Expert
Basic Statistics: Determine the critical values of the test statistic
Reference No:- TGS01920915

Now Priced at $30 (50% Discount)

Recommended (93%)

Rated (4.5/5)