Confidence interval of the true proportion
A recent study of 200 people in Miami found 54 were obese. Determine the 95% confidence interval of the true proportion of individuals living in Miami who are obese?
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Use standard normal distribution to approximate. Seventy-seven percent of homes have a telephone answering device. In a random sample of 290 homes, what is the probability that 200 or less do not have an answering device?
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Test these hypotheses using alfa=0.05. What are your conclusions? Determine the P value for this test. Develop a 95 percent confidence interval on the mean shaft diameter.
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