Find standard deviation of number of flaws selected yard


1) The survey inquires the random sample of 1500 adults in Ohio if they support the increase in state sales tax from 5% to 6%, with extra revenue going to education. Consider X denote number in sample that say they support increase. Assume that 40% of all adults in Ohio support increase.

i. Mean of X is? ii. Standard deviation of X is?

2) The garment manufacturer knows that number of flaws per square yard in the particular kind of cloth that he buys differs with the average of 1.3 flaws per square yard. Count X of flaws per square yard can be modeled by the Poisson distribution. Standrd divation of number of flaws is the randomly selected yard of cloth is?

i. 1.14 ii.1.30 iii. 1.61 iv.1.69

Mean number of flaws in 5 square yards of the cloth is?

i. 0.26 ii. 1.14 iii. 1.30 iv. 6.5

Probability of zero flaws in the square yard is 0.3012. The particular garment needs 3 square yards of cloth. Probability of zero flaws in 3 square yards of material is:

i. 0.0273 ii.0.0907 iii. 0.1004 iv.0.9036

Probability of at most 3 flaws in the randomly selected yard of cloth is?

i. 0.0998 ii. 0.1429 iii. 0.8571 iv. 09569

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Mathematics: Find standard deviation of number of flaws selected yard
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