Problem: Just as in the linkage mapping activity, students are looking at the data from a cross between a doubly homozygous recessive fly and a doubly heterozygous fly (who was produced from crossing a doubly homozygous dominant fly with a doubly homozygous recessive fly). Dominant alleles: wild type normal aristae, wild type normal wings Recessive alleles: aristapedia, dichaete wings Resulting offspring flies from cross: 257 wild type normal aristae, wild type normal wings 44 wild type normal aristae, dichaete wings 40 aristapedia, wild type normal wings 251 aristapedia, dichaete wings Calculate the chi-square statistic to the nearest tenths place that tests against the prediction that the data set shows a 1:1:1:1 phenotype ratio.