An attacker at the base of a castle wall 375 m high throws


Compute each part of given question:

Question: An attacker at the base of a castle wall 3.75 m high throws a rock straight up with speed 8.50 m/s from a height of 1.60 m above the ground.

Part A: what is the rock speed at the top?

m/s

Part B: Find the change in speed of a rock thrown straight down from the top of the wall at an initial speed of 8.50 m/s and moving between the same two points.

m/s

Part C: Does the change in speed of the downward-moving rock agree with the magnitude of the speed change of the rock moving upward between the same elevations? Explain physically why it does or does not agree.

Hello Experts please provide me the detailed computation for above question.

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Physics: An attacker at the base of a castle wall 375 m high throws
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