Problem- if 100 kj of heat are added to a 155 g ice cube at


Problem- If 10.0 kj of heat are added to a 15.5 g ice cube at -5.00 degrees C what will be the resulting state and temperature of the water?

Liquid 13.9eC

Liquid 72.degrees C

Vapor 103 degrees C

Vapor 134 degrees C

Solid -4.85 degrees C

Anyone can tell me how to solve it step by step so that I will be able to understand what is going on?

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Chemistry: Problem- if 100 kj of heat are added to a 155 g ice cube at
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