A 1300-kg car is being driven up a 4.0° hill. The frictional force is directed opposite to the motion of the car and has a magnitude of f = 530 N. A force Farrowbold is applied to the car by the road and propels the car forward. In addition to these two forces, two other forces act on the car: its weight Warrowbold and the normal force FarrowboldN directed perpendicular to the road surface. The length of the road up the hill is 275 m. What should be the magnitude of Farrowbold, so that the net work done by all the forces acting on the car is +160 kJ?