Molarity in Nacl
The molarity of 0.006 mole of NaCl in 100 solutions will be: (i) 0.6 (ii) 0.06 (iii) 0.006 (iv) 0.066 (v) None of theseChoose the right answer from above.Answer: The right answer is (ii) M = n/ v(l)= 0.006/ 0.1 = 0.06
The molarity of 0.006 mole of NaCl in 100 solutions will be: (i) 0.6 (ii) 0.06 (iii) 0.006 (iv) 0.066 (v) None of theseChoose the right answer from above.Answer: The right answer is (ii)
M = n/ v(l)= 0.006/ 0.1 = 0.06
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Can someone please help me in getting through this problem. 1.0 gm of pure calcium carbonate was found to require 50 ml of dilute HCL for complete reaction. The strength of the HCL solution is given by: (a) 4 N (b) 2 N (c) 0.4 N (d) 0.2 N
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