--%>

Explain Solid Compound Formation.

In some two component, solid liquid systems, a solid compound forms.

In systems in which the components have an interaction for such other, a solid state compound of the two compounds of the two components can form.

Formic acid and formaide form a solid state, one-to-one compound. The effect on the freezing point diagram is shown in fig. 1, such diagrams are understandable on the basis of the discussion of the diagrammatic problems. Each half of the fig. corresponds to the simple eutectic diagrams treated there.

Solutions which on cooling reach line NM or RW of fig. give rise to solid formaide, respectively. Solutions which on cooling reach line PN or PQ give rise to a solid which is a compound containing equimolar amounts of formic acid, and at point N the solution is in equilibrium with the new compound and formaide. Points and Q represent two eutectics that generally have different temperatures.

Again, as in the preceding section, the initial slopes of the lines at M, P and R can be interpreted in terms of the enthalpy of fusion and the freezing point of the substance that separates out as a solid near these points. Likewise, the curves can be interpreted in terms of the solubility of these components and can be compared with the ideal solution expectations given by the above equation.

Compound formation in the solid state is frequently encountered with hydrates, the formation of hydrated compounds of sulphuric acid in the solid state. Again, such diagrams are easily understood as a series of simple eutectic diagrams side by side.

A complication does occur when a solid compound does not have sufficient stability to persist up to the temperature at which it would melt. In such cases the unstable solid breaks down into a solution, and the solid state of one or the other of the two components. This is illustrated by the system calcium fluoride calcium chloride, as shown in the fig. the decomposition of such a solid is referred to as a peritectic reaction or an incongruent melting. Thus the equimolar crystal: CaF2. CaCl2 of fig. breaks down at 737 degree C into a solution of composition B and solid CaF2. The dashed line shows how the diagram might have looked if the compound had survived to a real or congruent melting point. This line is helpful for visualizing the phase behavior but has, of course, no real significance.

Miscible solids: brief mention can be made, particularly in view of their importance as alloys, of system forming only one solid phase which is a solid solution. Such behavior is a result of complete mutual solubility of the solid phases in each other affects the phase diagram of a system that shows a simple eutectic. Such a partial solubility frequently occurs when the atoms of one component are small and can fit into the interstices of the lattice of the major component. In this way an interstitial alloy is formed. The carbon atoms in a carbon containing alloy are usually so accommodated.

Complete solubility of two solid phases usually results when the atoms of the two components are about the same size and can substitute for each other in the lattice to form a substitutional alloy. The system of copper and nickel shows this behavior. The upper of the two curves shows the temperature at which solutions of various compositions start to freeze. The lower curve gives the comparison of the solid which separates out at that freezing point. In this system the solid is always richer melting component than the solution from which it separates. The alloy consisting of 60 percent copper and 40 percent nickel is known as constantan.  

   Related Questions in Chemistry

  • Q : Molarity of Nacl solution When 5.85 g

    When 5.85 g of NaCl (having molecular weight 58.5) is dissolved in water and the solution is prepared to 0.5 litres, the molarity of the solution is: (i) 0.2 (ii) 0.4 (iii) 1.0 (iv) 0.1

  • Q : Application of colligative properties

    Choose the right answer from following. Colligative properties are used for the determination of: (a) Molar Mass (b) Equivalent weight (c) Arrangement of molecules (d) Melting point and boiling point (d) Both (a) and (b)  

  • Q : Statement of Henry law Determine the

    Determine the correct regarding Henry’s law: (1) The gas is in contact with the liquid must behave as an ideal gas (2) There must not be any chemical interaction among the gas and liquid (3) The pressure applied must be high (4) All of these.

  • Q : Alkaline medium The amount of KMnO 4

    The amount of KMnO4 required to prepare 100 ml of 0.1N solution in alkaline medium is: (a) 1.58 gm (b) 3.16 gm (c) 0.52 gm (d) 0.31 gmAnswer: (a) In alkaline medium KMnO4 act as ox

  • Q : Molecular crystals Among the below

    Among the below shown which crystal will be soft and have low melting point: (a) Covalent  (b) Ionic  (c) Metallic  (d) MolecularAnswer: (d) Molecular crystals are soft and have low melting point.

  • Q : Finding strength of HCL solution Can

    Can someone please help me in getting through this problem. 1.0 gm of pure calcium carbonate was found to require 50 ml of dilute  HCL for complete reaction. The strength of the HCL  solution is given by: (a) 4 N  (b) 2 N  (c) 0.4 N  (d) 0.2 N

  • Q : Describe Thermodynamics Properties The

    The free energy property leads to convenient expressions for the volume and pressure dependence of internal energy, enthalpy and the heat capacities.All the properties of a chemical system, a sample of a substance, or a mixture of substances have some fixe

  • Q : What are condensation polymers? Give

    These types of polymers are formed as a result of condensation reaction between monomer units. Some common examples are being discussed here: 1. Polyesters 2047_condensat</span></p>
                                        </div>
                                        <!-- /comment-box -->
                                    </li>
   
   </td>
	</tr><tr>
		<td>
       
      <li>
                                        <div class=

    Q : Reaction of calcium carbonate Give me

    Give me answer of this question. What is the volume of 0.1NHcl required to react completely with 1.0g of pure calcium carbonate : (Ca= 40, C= 12 and o = 16 ) (a)150cm3 (b)250cm3 (c)200cm3 (d)100cm3

    Q : Problem on relative humidity Relative

    Relative humidity is the ratio of the partial pressure of water in air to the partial pressure of water in air saturated with water at the same temperature, stated as a percentage: Relative  =

    Discover Q & A

    Leading Solution Library
    Avail More Than 1423128 Solved problems, classrooms assignments, textbook's solutions, for quick Downloads
    No hassle, Instant Access
    Start Discovering

    18,76,764

    1932118
    Asked

    3,689

    Active Tutors

    1423128

    Questions
    Answered

    Start Excelling in your courses, Ask an Expert and get answers for your homework and assignments!!

    Submit Assignment

    ©TutorsGlobe All rights reserved 2022-2023.