--%>

Explain Solid Compound Formation.

In some two component, solid liquid systems, a solid compound forms.

In systems in which the components have an interaction for such other, a solid state compound of the two compounds of the two components can form.

Formic acid and formaide form a solid state, one-to-one compound. The effect on the freezing point diagram is shown in fig. 1, such diagrams are understandable on the basis of the discussion of the diagrammatic problems. Each half of the fig. corresponds to the simple eutectic diagrams treated there.

Solutions which on cooling reach line NM or RW of fig. give rise to solid formaide, respectively. Solutions which on cooling reach line PN or PQ give rise to a solid which is a compound containing equimolar amounts of formic acid, and at point N the solution is in equilibrium with the new compound and formaide. Points and Q represent two eutectics that generally have different temperatures.

Again, as in the preceding section, the initial slopes of the lines at M, P and R can be interpreted in terms of the enthalpy of fusion and the freezing point of the substance that separates out as a solid near these points. Likewise, the curves can be interpreted in terms of the solubility of these components and can be compared with the ideal solution expectations given by the above equation.

Compound formation in the solid state is frequently encountered with hydrates, the formation of hydrated compounds of sulphuric acid in the solid state. Again, such diagrams are easily understood as a series of simple eutectic diagrams side by side.

A complication does occur when a solid compound does not have sufficient stability to persist up to the temperature at which it would melt. In such cases the unstable solid breaks down into a solution, and the solid state of one or the other of the two components. This is illustrated by the system calcium fluoride calcium chloride, as shown in the fig. the decomposition of such a solid is referred to as a peritectic reaction or an incongruent melting. Thus the equimolar crystal: CaF2. CaCl2 of fig. breaks down at 737 degree C into a solution of composition B and solid CaF2. The dashed line shows how the diagram might have looked if the compound had survived to a real or congruent melting point. This line is helpful for visualizing the phase behavior but has, of course, no real significance.

Miscible solids: brief mention can be made, particularly in view of their importance as alloys, of system forming only one solid phase which is a solid solution. Such behavior is a result of complete mutual solubility of the solid phases in each other affects the phase diagram of a system that shows a simple eutectic. Such a partial solubility frequently occurs when the atoms of one component are small and can fit into the interstices of the lattice of the major component. In this way an interstitial alloy is formed. The carbon atoms in a carbon containing alloy are usually so accommodated.

Complete solubility of two solid phases usually results when the atoms of the two components are about the same size and can substitute for each other in the lattice to form a substitutional alloy. The system of copper and nickel shows this behavior. The upper of the two curves shows the temperature at which solutions of various compositions start to freeze. The lower curve gives the comparison of the solid which separates out at that freezing point. In this system the solid is always richer melting component than the solution from which it separates. The alloy consisting of 60 percent copper and 40 percent nickel is known as constantan.  

   Related Questions in Chemistry

  • Q : Molecular Properties Symmetry Molecular

    Molecular orbitals and molecular motions belong to certain symmetry species of the point group of the molecule.Examples of the special ways in which vectors or functions can be affected by symmetry operations are illustrated here. All wave functions soluti

  • Q : HCl is polar or non-polar Can you

    Can you please illustrate that HCl is polar or non-polar? Briefly illustrate it.

  • Q : Question 6 A student was analyzing an

    A student was analyzing an unknown containing only Group IV cations. When the unknown was treated with 3M (NH4)2CO3 solution, a white precipitate formed. Because the acetic acid bottle was empty, the student used 6M HCl to dissolve the precipitate. Following the procedure of this experiment, the stu

  • Q : Chem Silicon has three naturally

    Silicon has three naturally occurring isotopes. 28Si, mass = 27.976927; 29Si, mass = 28.976495; 30Si, mass = 29.973770 and 3.10% abundance. What is the abundance of 28Si?

  • Q : Question based on maximum vapour

    Provide solution of this question. Which has maximum vapour pressure: (a) HI (b) HBr (c) HCl (d) HF

  • Q : Determining maximum Osmotic pressure

    Which of the following would have the maximum osmotic pressure (assume that all salts are 90% dissociated): (a) Decimolar aluminium sulphate (b) Decimolar barium chloride (c) Decimolar sodium sulphate (d) A solution obtained by mix

  • Q : Thermodynamics I) Sulphur dioxide (SO2)

    I) Sulphur dioxide (SO2) with a volumetric flow rate 5000cm3/s at 1 bar and 1000C is mixed with a second SO2 stream flowing at 2500cm3/s at 2 bar and 200C. The process occurs at steady state. You may assume ideal gas behaviour. For SO2 take the heat capacity at constant pressure to be CP/R = 3.267

  • Q : F-centres If a electron is present in

    If a electron is present in place of anion in a crystal lattice, then it is termed as: (a) Frenkel defect  (b) Schottky defect  (c) Interstitial defects (d) F-centre Answer: (d) When electrons are trapped in anion vacancies, thes

  • Q : Problem based on lowering in vapour

    Help me to solve this problem. An aqueous solution of glucose was prepared by dissolving 18 g of glucose in 90 g of water. The relative lowering in vapour pressure is: (a) 0.02 (b)1 (c) 20 (d)180

  • Q : Dipole moment of chloro-octane Describe

    Describe the dipole moment of chloro-octane in brief?