Describe Transformation Matrices.

Each symmetry operation can be represented by a transformation matrix.

You have seen what happens when a molecule is subjected to the symmetry operation that corresponds to any of the symmetry elements of the point group to which the molecule belongs. The molecule is simply transformed into itself. But the properties of the molecule in which we are interested are not necessarily so simply affected.

All properties, or motions, of a molecule, obtained perhaps as eigenfunctions of the corresponding operator, are related to the symmetry of the molecule. Let us illustrate this by exploring how the overall translational and rotational motions of any C2molecule, the H2O molecule for example, change when the various symmetry operations of the C2v group are applied.

Let the overall translational motions of the H2O molecules be represented by the x, y, and zvectors. Some of the symmetry operations, those of the E and σ'v symmetry elements, leave x unchanged. Others, those of the C2 and the σv symmetry elements, change the direction, or sign of x. If the new translational vectors are indicated by  primes, you can see that the effects of the symmetry operations on, for example, x are given by the set of +1, -1, +1, -1 and the effect onby the set of entries +1, -1, +1, -1.

Now let us see how the rotations of the molecule about the x, y, and z axe are affected by the symmetry operations. We can do so by drawing curly arrows to represent the motions that constitute these rotations. Inspection of the effect of the symmetry operations shows that the same as two of those found when we used the vectors that represent translational motions as our basis. The effect on Rz, as illustrated and leads to a new, fourth set of +1 and -1 terms.

The four different types of symmetry behaviour that have been discovered are collected in each row represents a symmetry species. Each symmetry species is given an identifying label. We use the axis of rotation, i.e. a species for species that is symmetric with respect to the axis of rotation, i.e. a species for which +1 is the entry under the symbol for the rotation operation. We use the symbol B to indicate a symmetric species that is antisymmetric, and has a -1 entry, for this rotation operation. Here we use an additional subscript labels, choosing the subscript 1 for the more symmetric species and 2 for the less symmetric species.

The H2O molecule, or the C2v, point group, provides a simple, and special, example. In this case the translation and rotation vectors can be chosen so that the symmetry operations change each vector into itself or into its opposite. The effect of the operations change each vector into itself or into opposite. The effect of the operations on each of these vectors is represented by a +1 ora -1. The symmetry species of the C2point group consists of sets containing +1 and -1 terms.

Transformation matrices: for some point groups the basis vectors that we use to study the effects of the symmetry operations become mixed as a result of these operations. Consider the three overall translation vectors of the NH3 molecule of the C3v point group. These and the symmetry elements of this group are nothing new enters when we consider the effects of the symmetry operations on the z vector. This vector is unchanged by each and every symmetry operation. Thus a set of +1 is shows how the z translation vector is transformed.

Now consider the effect of a C3v rotation, i.e. rotation by 1/3 revolution on the x and y vectors. The results have now the new position of x, that is, the vector of x' is related to the original vectors by

x' = -1/2x - √3/2y

The new vector y' that is produced from the original vector y is given by

y' = +√3/2x - 1/2y

The net effect of the operation C2 on the set of vectors x and y can be shown by the matrix equation

x'    -1/2  - √3/2   x

y'     √3/2   -1/2    y    

   Related Questions in Chemistry

  • Q : Problem on equilibrium composition The

    The catalytic dehydrogenation of 1-butene to 1,3-butadiene, C4H8(g) = C4H6(g)+H2(g) is carried out at 900 K and 1 atm.

    Q : Determining highest normality What is

    What is the correct answer. Which of the given solutions contains highest normality: (i) 8 gm of KOH/litre (ii) N phosphoric acid (iii) 6 gm of NaOH /100 ml (iv) 0.5M H2SO4

  • Q : Molar mass of compound The freezing

    The freezing point of a solution having 4.8 g of a compound in 60 g of benzene is 4.48. Determine the molar mass of the compound (Kf = 5.1 Km-1) , (freezing point of  benzene = 5.5oC)          &n

  • Q : Molarity of acid solution If 20ml of

    If 20ml of 0.4N, NaoH solution completely neutralises 40ml of a dibasic acid. The molarity of the acid solution is: (a) 0.1M (b) 0.2M  (c) 0.3M (d) 0.4M Choose the right answer fron above.

  • Q : Pressure and power for adiabatic

    a) Air flowing at 1 m3/s enters an adiabatic compressor at 20°C and 1 bar. It exits at 200°C. The isentropic efficiency of the compressor is 80%. Calculate the exit pressure and the power required. b) Steam enter

  • Q : Vapour pressure of benzene Give me

    Give me answer of this question. The vapour pressure of benzene at a certain temperature is 640mm of Hg. A non-volatile and non-electrolyte solid weighing 2.175g is added to 39.08g of benzene. The vapour pressure of the solution is 600,mm of Hg . What is the mo

  • Q : Problem on physical and thermodynamic

    The shells of marine organisms contain calcium carbonate CaCO3, largely in a crystalline form known as calcite. There is a second crystalline form of calcium carbonate known as aragonite. Physical and thermodynamic properties of calcite and aragonite at 298

  • Q : Functions of centrioles Describe

    Describe briefly the functions of centrioles?

  • Q : Mole fraction of solute The mole

    The mole fraction of the solute in 1 molal aqueous solution is: (a) 0.027 (b) 0.036 (c) 0.018 (d) 0.009What is the correct answer.

  • Q : Molarity of Barium hydroxide 25 ml of a

    25 ml of a solution of barium hydroxide on titration with 0.1 molar solution of the hydrochloric acid provide a litre value of 35 ml. The molarity of barium hydroxide solution will be: (i) 0.07 (ii) 0.14 (iii) 0.28 (iv) 0.35

©TutorsGlobe All rights reserved 2022-2023.