Arithmetic Operators, Increment and Decrement Operators


The arithmetic operators are the typical `+', `-', `*', and `/' (that is, truncating integer division if the operands are both int), and the remainder or the mod operator `%':

x = a%b;

Sets x to the remainder subsequent to a is divided by b (that is, a mod b). The outcomes are machine dependent unless a and b are both positive.

In arithmetic, char variables can generally be treated like int variables. Arithmetic on characters is quite legal, and frequently makes sense:

c = c + 'A' - 'a';

transforms a single lower case ASCII character stored in c to upper case, making utilization of the fact that corresponding ASCII letters are a fixed distance apart. Rule governing this arithmetic is that all chars are transformed to int prior to the arithmetic is completed. Beware that conversion might include sign-extension when the leftmost bit of a character is 1; the resultant integer may be negative. (This does not occur with genuine characters on any present machine.)

Therefore to transform a file into lower case: 

       main( ) {
               char c;
               while( (c=getchar( )) != '\0' )
                       if( 'A'<=c && c<='Z' )
                               putchar(c); }

Increment and Decrement Operators:

In addition to the common `-', C as well has two other interesting unary operators, `++' (that is, increment) and `--' (that is, decrement). Assume that we wish for to count the lines in a file. 

       main( ) {
               int c,n;
               n = 0;
               while( (c=getchar( )) != '\0' )
                       if( c == '\n' )
               printf("%d lines\n", n);       }

++n is equal to n=n+1 however clearer, specifically whenever n is a complicated expression.  `++' and `--' can be applied merely to int's and char's (and pointers that we haven't got to yet).

The unusual characteristic of `++' and `--' is that they can be employed either before or after a variable.

The value of ++k is a value of k subsequent to it has been incremented. The value of k++ is k previous to it is incremented. Assume that k is 5. Then

x = ++k;

increments k to 6 and then sets x to the resultant value, that is to 6. However,

x = k++;

first sets x to 5, and then increments k to 6. The incrementing result of ++k and k++ is similar, however their values are correspondingly 5 and 6.

Latest technology based Programming Languages Online Tutoring Assistance

Tutors, at the, take pledge to provide full satisfaction and assurance in Programming Languages help via online tutoring. Students are getting 100% satisfaction by online tutors across the globe. Here you can get homework help for Programming Languages, project ideas and tutorials. We provide email based Programming Languages help. You can join us to ask queries 24x7 with live, experienced and qualified online tutors specialized in Programming Languages. Through Online Tutoring, you would be able to complete your homework or assignments at your home. Tutors at the TutorsGlobe are committed to provide the best quality online tutoring assistance for Programming Languages Homework help and assignment help services. They use their experience, as they have solved thousands of the Programming Languages assignments, which may help you to solve your complex issues of Programming Languages. TutorsGlobe assure for the best quality compliance to your homework. Compromise with quality is not in our dictionary. If we feel that we are not able to provide the homework help as per the deadline or given instruction by the student, we refund the money of the student without any delay.

2015 ┬ęTutorsGlobe All rights reserved. TutorsGlobe Rated 4.8/5 based on 34139 reviews.