The three facts on the evaporation
Describe briefly the three facts on the evaporation?
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The three facts on evaporation are as follows:
a) 80 percent of evaporation comes from ocean.b) 20 percent of evaporation comes from internal water.c) The wind helps evaporation through moving it.
Phenol was initially obtained by fractional distillation of coal
The ionic radii of Rb+ and I- respectively are 1.46 Å and 2.16Å. The very most probable type of structure exhibited by it is: (a) CsCl type (b) ZnS type (c) Nacl type (d) CaF2 type Q : Explain Solid Compound Formation. In In some two component, solid liquid systems, a solid compound forms.In systems in which the components have an interaction for such other, a solid state compound of the two compounds of the two components can form.Formic acid and formaide form a solid state, one-to-one com
In some two component, solid liquid systems, a solid compound forms.In systems in which the components have an interaction for such other, a solid state compound of the two compounds of the two components can form.Formic acid and formaide form a solid state, one-to-one com
Help me to solve this Question. The number of moles of SO2Cl2 in 13.5 gm is in is : (a) 0.1 (b) 0.2 (c) 0.3 (d) 0.4
Give me answer of this question. The formula weight of H2SO4 is 98. The weight of the acid in 400mi of solution is: (a)2.45g (b) 3.92g (c) 4.90g (d) 9.8g
Mole fraction of any solution is equavalent to: (a) No. of moles of solute/ volume of solution in litter (b) no. of gram equivalent of solute/volume of solution in litters (c) no. of moles of solute/ Mass of solvent in kg (d) no. of moles of any
Can we demonstration the organic structure of cetearyl alcohol and state me what organic family it is?
Provide solution of this question. A 5 molar solution of H2SO4 is diluted from 1 litre to 10 litres. What is the normality of the solution : (a) 0.25 N (b) 1 N (c) 2 N (d) 7 N
Why oxidising character of oxoacids of halogens decreases as oxidation number increases?
How to obtain relation between Vm and Km,given k(sec^-1) = Vmax/mg of enzyme x molecular weight x 1min/60 sec S* = 4.576(log K -10.753-logT+Ea/4.576T).
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