--%>
Assignment Help - homework help

Problem on MM equation

How to obtain relation between Vm and Km,given k(sec^-1) = Vmax/mg of enzyme x molecular weight x 1min/60 sec S* = 4.576(log K -10.753-logT+Ea/4.576T).

E

Expert

Verified

According to M.M Equation,
                                
                           V = Vmax x {S]/Km + {S]
                
Since Vmax = ksec^-1 {Et}

V = Ksec^-1{Et} x {S}/Km + {S}

Substituting the given value of Ksec^-1 in the above equation,we get
 
V = Vmax x mol.wt x 1min/60 sec x {S}/mg of enzyme / Km +{S]

V = Vmax x mol.wt x {S}/mg of enzyme/Km +{S}

Substituting the given value of {S}

V = Vmax x mol.wt x 4.576(log K -10.753-logT+Ea/4.576T)/mg of enzyme/ Km +  4.576(log K -10.753-logT+Ea/4.576T)

   Related Questions in Chemistry

  • Q : State octet rule in chemistry Explain

    Explain what is octet rule in chemistry?

    		•
  • Q : Question based on strength of solution

    Help me to go through this problem. On dissolving 1 mole of each of the following acids in 1 litre water, the acid which does not give a solution of strength 1N is: (a) HCl (b) Perchloric acid (c) HNO3 (d) Phosphoric acid

    		•
  • Q : Facts on evaporation Illustrate the 3

    Illustrate the 3 facts on evaporation?

    		•
  • Q : Changes in matter law of chemical

    changes in matter law of chemical combination

    		•
  • Q : Mole fraction of solute The mole

    The mole fraction of the solute in 1 molal aqueous solution is: (a) 0.027 (b) 0.036 (c) 0.018 (d) 0.009What is the correct answer.

    		•
  • Q : Problem on mol fraction of naphthalene

    At 20°C the solubility of solid naphthalene in hexane is 0.09 mol/mol of solution. Use this information and the data below to estimate the following for this system: a) The mol fraction of naphthalene in the vapour phase in equ

    		•
  • Q : Molarity of HCl solution 20 ml of HCL

    20 ml of HCL solution needs 19.85 ml of 0.01M NaOH solution for complete neutralization. Morality of the HCL solution is:  (i) 0.0099 (ii) 0.099 (iii) 0.99 (iv) 9.9 Choose the right answer from above.

    		•
  • Q : Liquid Vapour Free Energies The free

    The free energy of a component of a liquid solution is equal to its free energy in the equilibrium vapour.Partial molal free energies let us deal with the free energy of the components of a solution. We use these free energies, or simpler concentration ter

    		•
  • Q : Problem on Clausius equation of state

    If a gas can be described by the Clausius equation of state: P (V-b) = RT Where b is a constant, then:  (a) Obtain an expression for the residual vo

    		•
  • Q : Finding strength of HCL solution Can

    Can someone please help me in getting through this problem. 1.0 gm of pure calcium carbonate was found to require 50 ml of dilute  HCL for complete reaction. The strength of the HCL  solution is given by: (a) 4 N  (b) 2 N  (c) 0.4 N  (d) 0.2 N

    		•