--%>

Define Bond Energies - Bond Charges

Energy changes in some chemical reactions can be used to deduce the energies of chemical bonds.


Our understanding of the molecular basis of thermodynamic properties is extended when we ask why the enthalpy change for a reaction is what it is. We deduce, for example, from the data, the value of -802.34 kJ for ΔH°298 for the reaction:

2145_bond energy.png 
 
Why it is the enthalpy change has this value?

Two relatively small contributions to the ?H term can be recognized. One contribution comes from the difference in the normal products of the thermal energies of the molecules of the products and the reactants. Another small contribution due to the volume comes from the change in number of moles of reagents.

These minor complicating contributions can be avoided by using ?H00 = ?UC values such as those o f appendix table to calculate the ?U00 value of - 804.2 kJ for the methane combination reaction. Now we ask about the molecular basis of this energy difference.

To answer such question, we adopt a traditional chemical idea. We think of the energies of many substances in terms of the chemical bonds that we imagine to be holding the atoms together. The energy of one substance compared to that of another substance is said to be due primarily to the energy "strength" of the chemical bonds.

Standard enthalpies of atomic species: we need to justify the energy data for the free gaseous atoms to calculate the energy change when the molecules of a substance are broken up into free atoms.

Enthalpy and energy data can be taken for gaseous atomic substances. These data come, usually, from spectroscopic rather from calorimetric measurements. For diametric molecules, spectral studies show the energy for breakup of these molecules into atoms. Results from the original molecules and the atoms produced, all in their lowest energy, or ground states, can be deduced from the spectral data. Thus we arrive directly at data for ?H°f,0. these energy data for atomic species can be extended to give enthalpy values, as illustrated by some of the entries in bond energies.

Bond energies: with the data begin by considering reactions that are easily given a bond energy interpretation. For example, the ΔH° ƒ, 0 can be used to obtain:

199_bond energy1.png

   Related Questions in Chemistry

  • Q : Haloalkene with the help of polarity of

    with the help of polarity of c-x bond show that aryl halides are less reactive than alkyl halides

  • Q : Molarity of acid solution If 20ml of

    If 20ml of 0.4N, NaoH solution completely neutralises 40ml of a dibasic acid. The molarity of the acid solution is: (a) 0.1M (b) 0.2M  (c) 0.3M (d) 0.4M Choose the right answer fron above.

  • Q : Death cap musrooms the death cap

    the death cap mushroom based on your knowledge of the biochemistry of dna and rna

  • Q : Calculating weight of acid Give me

    Give me answer of this question. The formula weight of H2SO4 is 98. The weight of the acid in 400mi of solution is: (a)2.45g (b) 3.92g (c) 4.90g (d) 9.8g

  • Q : Molarity of cane sugar solution 171 g

    171 g of cane sugar (C12H22O11)  is dissolved in one litre of water. Find the molarity of the solution: (i) 2.0 M (ii) 1.0 M (iii) 0.5 M (iv) 0.25 M Choose the right answer from above.

  • Q : Osmotic Pressure The O.P. (Osmotic

    The O.P. (Osmotic Pressure) of equimolar solution of Urea, BaCl2 and AlCl3, will be in the order:(a) AlCl3 > BaCl2 > Urea  (b) BaCl2 > AlCl3 > Urea  (c) Urea > BaCl2<

  • Q : Linde liquefaction process Liquefied

    Liquefied natural gas (LNG) is produced using a Linde liquefaction process from pure methane gas at 3 bar and 280 K (conditions at point 1 in figure below). A three-stage compressor with interceding is used to compress the methane to 100 bar (point 2). The first stage

  • Q : Freezing point of equimolal aqueous

    The freezing point of equi-molal aqueous solution will be maximum for:            (a) C6H5NH3+Cl-(aniline hydrochloride)  (b) Ca(NO3

  • Q : Calculating number of moles from

    Choose the right answer from following. If 0.50 mol of CaCl2 is mixed with 0.20 mol of Na3PO4, the maximum number of moles of Ca3 (PO2)2 which can be formed: (a) 0.70 (b) 0.50 (c) 0.20 (d) 0.10