Explain Rotational Vibrational Spectra

The infrared spectrum of gas samples shows the effect of rotational-energy changes along with the vibrational energy change.

As we know from the interpretations given to thermodynamic properties of gases, gas molecules are simultaneously rotating and vibrating. It follows that an absorption spectrum or the Raman spectrum of a gas might show the effects of changes in both rotational and vibrational energies. The expanded view of the infrared absorption band of HCl shows the band structure that must be attributed to the rotational energy changes accompanying this fundamental, v = 0 to v =1, vibrational transition.

The rigid-rotor and harmonic-oscillator expressions can be combined to give the rotation vibration allowed energy expression

εrot-vib = (v + 1/2)hvvib + BJ(J + 1) v = 0, 1, 2 ...; J = 0, 1, 2 ....

The energy pattern that includes only the v = 0 and v = 1 levels and a few of the rotational levels for each vibrational state.

Analysis of the absorption spectrum for gas-phase molecules for which the energy expression applies can be made on the basis of this energy pattern and the selection rules that govern the transitions. Again the rules Δv = ±1 and ΔJ = ±1 hold, and while only Δv = ±1 and ΔJ = -1 are now possible. Transitions allowed by these rules are included.

The energies of the various transitions are determined by the rotation vibration energy expressions. In each case the vibrational contribution is given by hvvib. The rotational contributions are obtained and the J value in the v = 0 state, which determines the J value in thev = 1 state. Expressions for the energies of the components of an HCl type of rotation vibration band. Now, the transition lines have been placed on the diagram in order of increasing ε, or v?, from left to right. They thus are obtained as the expected components of a rotation-vibration band.

This analysis leads to a set of equally spaced components of the spectral band at either side of the band center. The spacing can be identified as 2B?. At the band center a gap equal to 4B?occurs. All these features are generally borne out by the rotation vibration band of HCl.

The lower frequency side of a rotation vibration band is known as the P branch, and the high frequency side as the R branch. In some cases, but not in the HCl type of spectrum, a central branch known as the Q branch occurs.

This analysis shows that a measurement of the spacing of the components of a value for the moment of inertia I. values so obtained are often not as precisely determined as those from microwave studies of pure rotational spectra, but the infrared region is more easily accessible. A similar analysis of the rotation vibration band structure could be carried through for Raman bands.

Dependence of bond length on vibrational state: now it is time to admit, that the spacing between the components of a rotation vibration band is not, in fact, constant. The rigid rotor harmonic oscillator model can be easily modified so that the observed spreading out of the P branch and closing up of the R branch can be accounted for. We recognize that the average bond length in the v = 1 vibrational state. (You might even anticipate that the average bond length in the v = 1vibrational state need not to be identical to the average bond length in the v = 0 state. If the bond length is different in different vibrational states, so also are the moment of inertia and the rotational constant B. let us denote the rotational constant for the ground v = 0 sate by B0 and that for the v = 1 state by B1. Now the spacing between the components of a rotation vibration band depends on hvvib and on both B0 and B1. The energy change for the first line of the Rbranch, for example, is hvvib + 2B1, and that of the second line is hvvib + 6B1 - 2B0. Thus, the spacing between these lines is 2(2B1 - B0). The spacing between the next two lines of the Rbranch is 2(3B1 - 2B0). Thus, in general, the spacing between successive pairs of lines of the Rbranch and the P branch will depend on B1 and B0 and will be constant only if B1 = B0. In spite of this added complexity, the value of B1 and B0 can be easily by modifying the graphical treatment.

The energy of difference between pairs of transitions that start at the same J level of the v = 0state can be used to deduce B1, the rotational constant for the v = 1 state. The energy difference between pairs of transitions that end at the same J level of the v = 1 state that gives result for B1 and pairs that give results for B0. Additional pairs can be treated, and average values of B1 and B0 can be obtained for all suitable component pairs. The validity of the model is determined by the constancy of the values for B1 and B0 obtained from the various component pairs. 

   Related Questions in Chemistry

  • Q : Explain the process of adsorption of

    The extent of adsorption of a gas on a solid adsorbent is affected by the following factors: 1. Nature of the gas Since physical adsorption is non-specific in nature, every gas will get adsorbed on the

  • Q : Explain gels and its various categories.

    Certain sols have the property of setting to a semi-solid, jelly-like form by enclosing the entire amount of liquid within itself when they are present at high concentrations. This process is called gelation and colloidal systems with jelly-like appearance are known as gels. Some common examples

  • Q : Group Cations Explain how dissolving

    Explain how dissolving the Group IV carbonate precipitate with 6M CH3COOH, followed by the addition of extra acetic acid, establishes a buffer with a pH of approximately

  • Q : Lab question Explain how dissolving the

    Explain how dissolving the Group IV carbonate precipitate with 6M CH3COOH, followed by the addition of extra acetic acid, establishes a buffer with a pH of approximately 5.

  • Q : P- block why pentahalids are more

    why pentahalids are more covalent than tetrahalids

  • Q : Short note on the function of

    Write down a short note on the function of mitochondria?

  • Q : Mass percent Help me to go through this

    Help me to go through this problem. 10 grams of a solute is dissolved in 90 grams of a solvent. Its mass percent in solution is : (a) 0.01 (b) 11.1 (c)10 (d) 9

  • Q : Explain Rotational Vibrational Spectra

    The infrared spectrum of gas samples shows the effect of rotational-energy changes along with the vibrational energy change.As we know from the interpretations given to thermodynamic properties of gases, gas molecules are simultaneously rotating and vibrating. It follows that an absor

  • Q : Molarity of acid solution If 20ml of

    If 20ml of 0.4N, NaoH solution completely neutralises 40ml of a dibasic acid. The molarity of the acid solution is: (a) 0.1M (b) 0.2M  (c) 0.3M (d) 0.4M Choose the right answer fron above.

  • Q : Isotonic Solutions Which one of the

    Which one of the following pairs of solutions can we expect to be isotonic at the same temperature:(i) 0.1M Urea and 0.1M Nacl  (ii) 0.1M Urea and 0.2M Mgcl2  (iii) 0.1M Nacl and 0.1M Na2SO4  (iv) 0.1M Ca(NO3<

©TutorsGlobe All rights reserved 2022-2023.