You have a real battery with an unknown voltage V, an unknown internal resistance a real voltmeter with resistance of 2.00000000 x105 Ω (200 k Ω) and a real ammeter with a resistance of 1.00000000x102 Ω (100 Ω). Normally the resistance of the ammeter should be much smaller than the resistance of any of the nonwire parts of the circuit and the resistance of the voltmeter should be much larger. But we don't know how small or large Rint is so we need to explicitly take these resistances into account. When the ammeter is hooked up to the real battery by itself, it reads 1.198459 Amps. When the voltmeter is hooked up to the battery by itself (one end on each terminal of the battery) it reads 119.999923 Volts.
a) What is the internal resistance Rint of the real battery?
b) What is the voltage V of the real battery?