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When 0430 mole of titanium is combusted in a bomb

When .0430 mole of titanium is combusted in a bomb calorimeter, the temperature of the calorimeter increases from 30.00degress Celsius to 91.60 degrees Celsius. In a separate experiment, the heat capacity of the calorimeter is measured to be 9.84kJ/K. The heat of reaction for the combustion of a mole of Ti in this calorimeter is ______?

The answer is supposed to be -1.52*10^4

Can someone please explain the process of how to get this answer?

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