What would be the difference between the time t measured by an observer moving at 30 rm m/s and the proper time t_0 for a proper time interval of 1 hour (3600 rm s)? The answer is small but nonzero. You will need to find an expression for the time difference using the approximation given in this problem before you substitute in the numbers; otherwise your calculator will just give zero. Express your answer in seconds to three significant figures. Use c = 3 times 10^8 ; rm m/s.