What is the volume of iron contained between the marks labeled 3.10cm and 3.50cm? A solid cylinder of iron of circular cross section with a radius of1.500cm had a ruler etched along its length. The volume of a cylinder is πr2l, where π= 3.1416, r is the radius, and l is the length.
Would the answer be:
volume = (3.1416)(1.500cm)2(3.50cm-3.10cm)
= (3.1416)(2.25cm2)(.4cm)
= 2.82744cm3